[c#] Getting mouse position in c#

How do I get the mouse position? I want it in term of screen position.

I start my program I want to set to the current mouse position.

Location.X = ??
Location.Y = ??

Edit: This must happen before the form is created.

If you don't want to reference Forms you can use interop to get the cursor position:

using System.Runtime.InteropServices;
using System.Windows; // Or use whatever point class you like for the implicit cast operator

/// <summary>
/// Struct representing a point.
/// </summary>
[StructLayout(LayoutKind.Sequential)]
public struct POINT
{
    public int X;
    public int Y;

    public static implicit operator Point(POINT point)
    {
        return new Point(point.X, point.Y);
    }
}

/// <summary>
/// Retrieves the cursor's position, in screen coordinates.
/// </summary>
/// <see>See MSDN documentation for further information.</see>
[DllImport("user32.dll")]
public static extern bool GetCursorPos(out POINT lpPoint);

public static Point GetCursorPosition()
{
    POINT lpPoint;
    GetCursorPos(out lpPoint);
    // NOTE: If you need error handling
    // bool success = GetCursorPos(out lpPoint);
    // if (!success)
        
    return lpPoint;
}

Initialize the current cursor. Use it to get the position of X and Y

this.Cursor = new Cursor(Cursor.Current.Handle);
int posX = Cursor.Position.X;
int posY = Cursor.Position.Y;

To get the position look at the OnMouseMove event. The MouseEventArgs will give you the x an y positions...

protected override void OnMouseMove(MouseEventArgs mouseEv) 

To set the mouse position use the Cursor.Position property.

http://msdn.microsoft.com/en-us/library/system.windows.forms.cursor.position.aspx

To answer your specific example:

// your example
Location.X = Cursor.Position.X;
Location.Y = Cursor.Position.Y;

// sample code
Console.WriteLine("x: " + Cursor.Position.X + " y: " + Cursor.Position.Y);

Don't forget to add using System.Windows.Forms;, and adding the reference to it (right click on references > add reference > .NET tab > Systems.Windows.Forms > ok)

You must also have the following imports in order to import the DLL

using System.Runtime.InteropServices;
using System.Diagnostics;

Cursor.Position will get the current screen poisition of the mouse (if you are in a Control, the MousePosition property will also get the same value).

To set the mouse position, you will have to use Cursor.Position and give it a new Point:

Cursor.Position = new Point(x, y);

You can do this in your Main method before creating your form.

If you need to get current position in form's area(got experimentally), try:

Console.WriteLine("Current mouse position in form's area is " + 
    (Control.MousePosition.X - this.Location.X - 8).ToString() +
    "x" + 
    (Control.MousePosition.Y - this.Location.Y - 30).ToString()
);

Although, 8 and 30 integers were found by experimenting.

Would be awesome if someone could explain why exactly these numbers ^.

Also, there's another variant(considering code is in Form's CodeBehind):

Point cp = PointToClient(Cursor.Position); // Getting a cursor's position according form's area
Console.WriteLine("Cursor position: X = " + cp.X + ", Y = " + cp.Y);

System.Windows.Forms.Control.MousePosition

Gets the position of the mouse cursor in screen coordinates. "The Position property is identical to the Control.MousePosition property."

   internal static class CursorPosition {
  [StructLayout(LayoutKind.Sequential)]
  public struct PointInter {
     public int X;
     public int Y;
     public static explicit operator Point(PointInter point) => new Point(point.X, point.Y);       
  }

  [DllImport("user32.dll")]
  public static extern bool GetCursorPos(out PointInter lpPoint);

  // For your convenience
  public static Point GetCursorPosition() {
     PointInter lpPoint;
     GetCursorPos(out lpPoint);
     return (Point) lpPoint;
  }

}