Java Scanner class reading strings

Question

I got the following code   int nnames  String names     System out print  How many names are you going to save      Scanner in   new Scanner System in   nnames   in nextInt    names   new String nnames    for  int i   0  i  lt  names length  i       System out print  Type a name        names i    in nextLine        And the output for that code is the following   How many names are you going to save 3  Type a name  Type a name  John Doe Type a name  John Lennon   Notice how it skipped the first name entry   It skipped it and went straight for the second name entry  I have tried looking what causes this but I don t seem to be able to nail it  I hope someone can help me  Thanks

User · Answer

use sc nextLine    two time so that we can read the last line of string   sc nextLine   sc nextLine

User · Answer

It s because the    in nextInt    doesn t change line  So you first  enter   after you press 3     cause the endOfLine  read by your in nextLine   in your loop   Here a small change that you can do   int nnames      String names         System out print  How many names are you going to save          Scanner in   new Scanner System in       nnames   Integer parseInt in nextLine         names   new String nnames        for  int i   0  i  lt  names length  i                 System out print  Type a name                  names i    in nextLine

User · Answer

This because in nextInt   only receive a int number  doesn t receive a new line  So you input 3 and press  Enter   the end of line is read by in nextline     Here is my code   int nnames  String names     System out print  How many names are you going to save      Scanner in   new Scanner System in   nnames   in nextInt    in nextLine    names   new String nnames    for  int i   0  i  lt  names length  i             System out print  Type a name              names i    in nextLine

User · Answer

You could have simply replaced  names i    in nextLine     with names i    in next     Using next   will only return what comes before a space  nextLine   automatically moves the scanner down after returning the current line

User · Answer

The reason for the error is that the nextInt only pulls the integer  not the newline  If you add a in nextLine   before your for loop  it will eat the empty new line and allow you to enter 3 names   int nnames  String names     System out print  How many names are you going to save      Scanner in   new Scanner System in   nnames   in nextInt     names   new String nnames   in nextLine    for  int i   0  i  lt  names length  i             System out print  Type a name              names i    in nextLine        or just read the line and parse the value as an Integer   int nnames  String names     System out print  How many names are you going to save      Scanner in   new Scanner System in   nnames   Integer parseInt in nextLine   trim      names   new String nnames   for  int i   0  i  lt  names length  i             System out print  Type a name              names i    in nextLine

[java] Java Scanner class reading strings

Examples related to java

Examples related to string

Examples related to duplicates

Examples related to java.util.scanner