[c#] How to calculate the IP range when the IP address and the netmask is given?

When a IP-Range is written as aaa.bbb.ccc.ddd/netmask (CIDR Notation) I need to calculate the first and the last included ip address in this range with C#.

Example:

Input: 192.168.0.1/25

Result: 192.168.0.1 - 192.168.0.126

I would recommend the use of IPNetwork Library https://github.com/lduchosal/ipnetwork. As of version 2, it supports IPv4 and IPv6 as well.

IPv4

  IPNetwork ipnetwork = IPNetwork.Parse("192.168.0.1/25");

  Console.WriteLine("Network : {0}", ipnetwork.Network);
  Console.WriteLine("Netmask : {0}", ipnetwork.Netmask);
  Console.WriteLine("Broadcast : {0}", ipnetwork.Broadcast);
  Console.WriteLine("FirstUsable : {0}", ipnetwork.FirstUsable);
  Console.WriteLine("LastUsable : {0}", ipnetwork.LastUsable);
  Console.WriteLine("Usable : {0}", ipnetwork.Usable);
  Console.WriteLine("Cidr : {0}", ipnetwork.Cidr);

Output

  Network : 192.168.0.0
  Netmask : 255.255.255.128
  Broadcast : 192.168.0.127
  FirstUsable : 192.168.0.1
  LastUsable : 192.168.0.126
  Usable : 126
  Cidr : 25

Have fun !

Invert mask (XOR with ones), AND it with IP. Add 1. This will be the starting range. OR IP with mask. This will be the ending range.

Input: 192.168.0.1/25

The mask is this part: /25

To find the network address do the following:

• Subtract the mask from the ip length (32 - mask) = 32 - 25 = 7 and take those bits from the right

• In the given ip address I.e: 192.168.0.1 in binary is: 11111111 11111111 00000000 00000001 Now, taking 7 bits from right '0' 1111111 11111111 00000000 00000000 Which in decimal is: 192.168.0.0 (this is the network address)

To find first valid/usable ip address add +1 to network address I.e: 192.168.0.1

To find the last/broadcast address the procedure is same as that of finding network address but here you have to make (32-mask) bits from right to '1'

I.e: 11111111 11111111 00000000 01111111 Which in decimal is 192.168.0.127

To find the last valid/usable ip address subtract 1 from the broadcast address I.e: 192.168.0.126

I'll just post the code:

IPAddress ip = new IPAddress(new byte[] { 192, 168, 0, 1 });
int bits = 25;

uint mask = ~(uint.MaxValue >> bits);

// Convert the IP address to bytes.
byte[] ipBytes = ip.GetAddressBytes();

// BitConverter gives bytes in opposite order to GetAddressBytes().
byte[] maskBytes = BitConverter.GetBytes(mask).Reverse().ToArray();

byte[] startIPBytes = new byte[ipBytes.Length];
byte[] endIPBytes = new byte[ipBytes.Length];

// Calculate the bytes of the start and end IP addresses.
for (int i = 0; i < ipBytes.Length; i++)
{
    startIPBytes[i] = (byte)(ipBytes[i] & maskBytes[i]);
    endIPBytes[i] = (byte)(ipBytes[i] | ~maskBytes[i]);
}

// Convert the bytes to IP addresses.
IPAddress startIP = new IPAddress(startIPBytes);
IPAddress endIP = new IPAddress(endIPBytes);

I know this is an older question, but I found this nifty library on nuget that seems to do just the trick for me:

http://nuget.org/packages/TakeIo.NetworkAddress/

You might already know this, but to check that you're getting this stuff right have a look at http://www.subnet-calculator.com/ - you can see there how the bits represent the network and host portions of the address.

I learned this shortcut from working at the network deployment position. It helped me so much, I figured I will share this secret with everyone. So far, I have not able to find an easier way online that I know of.

For example a network 192.115.103.64 /27, what is the range?

just remember that subnet mask is 0, 128, 192, 224, 240, 248, 252, 254, 255

255.255.255.255 11111111.11111111.11111111.11111111 /32

255.255.255.254 11111111.11111111.11111111.11111110 /31

255.255.255.252 11111111.11111111.11111111.11111100 /30

255.255.255.248 11111111.11111111.11111111.11111000 /29

255.255.255.240 11111111.11111111.11111111.11110000 /28

255.255.255.224 11111111.11111111.11111111.11100000 /27

255.255.255.192 11111111.11111111.11111111.11000000 /26

255.255.255.128 11111111.11111111.11111111.10000000 /25

255.255.255.0 11111111.11111111.11111111.00000000 /24

from /27 we know that (11111111.11111111.11111111.11100000). Counting from the left, it is the third number from the last octet, which equal 255.255.255.224 subnet mask. (Don't count 0, 0 is /24) so 128, 192, 224..etc

Here where the math comes in:

use the subnet mask - subnet mask of the previous listed subnet mask in this case 224-192=32

We know 192.115.103.64 is the network: 64 + 32 = 96 (the next network for /27)

which means we have .0 .32. 64. 96. 128. 160. 192. 224. (Can't use 256 because it is .255)

Here is the range 64 -- 96.

network is 64.

first host is 65.(first network +1)

Last host is 94. (broadcast -1)

broadcast is 95. (last network -1)