Get the date a day before current time in Bash

Question

How can I print the date which is a day before current time in Bash

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bin bash OFFSET 1  eval  date   day  d  month  m  year  Y     Subtract offset from day  if it goes below one use  cal    to determine the number of days in the previous month  day  expr  day -  OFFSET  if    day -le 0    then month  expr  month - 1  if    month -eq 0    then year  expr  year - 1  month 12 fi set  cal  month  year  xday       day  expr  xday    day  fi echo  year- month- day

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yesterday  date -d  -1 day   F    Puts yesterday s date in YYYY-MM-DD format into variable  yesterday

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If you have BSD  OSX  date you can do it like this   date -j -v-1d Wed Dec 14 15 34 14 CET 2011   Or if you want to do date calculations on an arbitrary date   date -j -v-1d -f   Y- m- d   2011-09-01     Y- m- d  2011-08-31

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Advanced Bash-scripting Guide  date   Y  m  d -d  yesterday    For details about the date format see the man page for date  date --date  -1 day

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Well this is a late answer but this seems to work         YESTERDAY  TZ GMT 24 date   d- m- Y        echo  YESTERDAY

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Use Perl instead perhaps   perl -e  print scalar localtime  time - 86400       n      Or  use nawk and  ab use  usr bin adb   nawk  BEGIN printf  0t d Y n   srand  -86400     adb   Came across this too     insane    usr bin truss  usr bin date 2 gt  amp 1   nawk -F     time       gsub         2  printf  0t d Y n    2-86400     adb

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MAC OSX  For yesterday s date   date -v-1d   F   where 1d defines current day minus 1 day  Similarly   date -v-1w   F - for previous week date  date -v-1m   F - for previous month date  IF YOU HAVE GNU DATE   date --date  1 day ago    More info  https   www cyberciti biz tips linux-unix-get-yesterdays-tomorrows-date html

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if you have GNU date and i understood you correctly    date   Y  m  d -d  yesterday  2009 11 09   or      date   Y  m  d -d  1 day ago  2009 11 09

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date   Y  m  d awk -vFS     -vOFS        3  3-1 print   2009 11 9

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You could do a simple calculation  pimped with an regex  if the chosen date format is  YYYYMM    echo      date    Y m   - 1     sed -e  s 99  12     In January of 2020 it will return 201912  -  But  it s only a workaround  when date does not have calculation options and other dateinterpreter options  e g  using perl  not available  -

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DST aware solution     Manipulating the Timezone is possible for changing the clock some hours  Due to the daylight saving time  24 hours ago can be today or the day before yesterday     You are sure that yesterday is 20 or 30 hours ago  Which one  Well  the most recent one that is not today     echo -e    TZ GMT 30 date   Y- m- d  n  TZ GMT 20 date   Y- m- d     grep -v   date   Y- m- d    tail -1   The -e parameter used in the echo command is needed with bash  but will not work with ksh  In ksh you can use the same command without the -e flag     When your script will be used in different environments  you can start the script with    bin ksh or    bin bash  You could also replace the  n by a newline     echo    TZ GMT 30 date   Y- m- d    TZ GMT 20 date   Y- m- d     grep -v   date   Y- m- d    tail -1

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date --date  -1 day

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date -d  yesterday     Y- m- d    or  date   date -d  yesterday     Y- m- d   echo  date

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Try the below code   which takes care of the DST part as well   if     date   w  -eq   date -u   w     then   tz     10  gmthour - 10  localhour    else   tz     24 - 10  gmthour   10  localhour    fi echo  tz myTime  TZ GMT  tz date    Y m d     Courtsey Ansgar Wiechers

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Sorry not mentioning I on Solaris system  As such  the -date switch is not available on Solaris bash   I find out I can get the previous date with little trick on timezone   DATE  TZ MYT 16 date   Y- m- d  r  echo  DATE

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date --date  -1 day

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Not very sexy but might do the job   perl -e  my   sec  min  hour  mday  mon  year  wday  yday  isdst    localtime time - 86400   year    1900   mon   1  printf   YESTERDAY   04d 02d 02d  n    year   mon   mday     Formated from  martin clayton  answer

[bash] Get the date (a day before current time) in Bash

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