Is there any way to have nested objects in JSON so I don't have to make arrays out of everything? For my object to be parsed without error I seem to need a structure like this:
{"data":[{"stuff":[
{"onetype":[
{"id":1,"name":"John Doe"},
{"id":2,"name":"Don Joeh"}
]},
{"othertype":[
{"id":2,"company":"ACME"}
]}]
},{"otherstuff":[
{"thing":
[[1,42],[2,2]]
}]
}]}
If I fetch this object into a variable called "result" I have to access the nested objects like this:
result.data[0].stuff[0].onetype[0]
and
result.data[1].otherstuff[0].thing[0]
This seems clumsy and redundant to me, if possible I would prefer:
result.stuff.onetype[0]
and
result.otherstuff.thing
But how can I use the object keys directly when everything is an array? To my confused and uneducated mind something like this would seem more appropriate:
{"data":
{"stuff":
{"onetype":[
{"id":1,"name": ""},
{"id":2,"name": ""}
]}
{"othertype":[
{"id":2,"xyz": [-2,0,2],"n":"Crab Nebula","t":0,"c":0,"d":5}
]}
}
{"otherstuff":
{"thing":
[[1,42],[2,2]]
}
}
}
I've probably misunderstood something fundamental here, but I cannot get the jQuery parser (nor the native FF parser used by jQuery 1.4) to accept the second style object. If anyone can enlighten me it would be gratefully appreciated!
This question is related to
javascript
jquery
json
syntax
parsing
Every object has to be named inside the parent object:
{ "data": {
"stuff": {
"onetype": [
{ "id": 1, "name": "" },
{ "id": 2, "name": "" }
],
"othertype": [
{ "id": 2, "xyz": [-2, 0, 2], "n": "Crab Nebula", "t": 0, "c": 0, "d": 5 }
]
},
"otherstuff": {
"thing":
[[1, 42], [2, 2]]
}
}
}
So you cant declare an object like this:
var obj = {property1, property2};
It has to be
var obj = {property1: 'value', property2: 'value'};
You have too many redundant nested arrays inside your jSON data, but it is possible to retrieve the information. Though like others have said you might want to clean it up.
use each() wrap within another each() until the last array.
for result.data[0].stuff[0].onetype[0]
in jQuery you could do the following:
`
$.each(data.result.data, function(index0, v) {
$.each(v, function (index1, w) {
$.each(w, function (index2, x) {
alert(x.id);
});
});
});
`
Source: Stackoverflow.com