Counting the Number of keywords in a dictionary in python

Question

I have a list of words in a dictionary with the value   the repetition of the keyword but I only want a list of distinct words so I wanted to count the number of keywords  Is there a way to count the number of keywords or is there another way I should look for distinct words

User · Answer

In order to count the number of keywords in a dictionary  def dict finder dict finders       x input  quot Enter the thing you want to find   quot       if x in dict finders          print  quot Element found quot       else          print  quot Nothing found  quot

User · Answer

Some modifications were made on posted answer UnderWaterKremlin to make it python3 proof  A surprising result below as answer   System specs    python  3 7 4  conda   4 8 0 3 6Ghz  8 core  16gb    import timeit  d    x  x  2 for x in range 1000    print  d  print  len d     1000  print  len d keys       1000  print  timeit timeit  len  x  x  2 for x in range 1000      number 100000            1  print  timeit timeit  len  x  x  2 for x in range 1000   keys      number 100000     2   Result   1    37 0100378  2    37 002148899999995  So it seems that len d keys    is currently faster than just using len

User · Answer

The number of distinct words  i e  count of entries in the dictionary  can be found using the len   function    gt  a     foo  42   bar  69   gt  len a  2   To get all the distinct words  i e  the keys   use the  keys   method    gt  list a keys      foo    bar

User · Answer

len yourdict keys      or just  len yourdict    If you like to count unique words in the file  you could just use set and do like  len set open yourdictfile  read   split

User · Answer

If the question is about counting the number of keywords then would recommend something like  def countoccurrences store  value       try          store value    store value    1     except KeyError as e          store value    1     return   in the main function have something that loops through the data and pass the values to countoccurrences function  if   name         main         store          list     a    a    b    c    c       for data in list          countoccurrences store  data      for k  v in store iteritems            print  Key     k     has occurred      str v      times    The code outputs   Key a has occurred 2 times Key c has occurred 2 times Key b has occurred 1 times

User · Answer

Calling len   directly on your dictionary works  and is faster than building an iterator  d keys    and calling len   on it  but the speed of either will negligible in comparison to whatever else your program is doing   d    x  x  2 for x in range 1000    len d    1000  len d keys      1000   timeit len d    41 9 ns    0 244 ns per loop  mean    std  dev  of 7 runs  10000000 loops each    timeit len d keys      83 3 ns    0 41 ns per loop  mean    std  dev  of 7 runs  10000000 loops each

[python] Counting the Number of keywords in a dictionary in python

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