Putting a simple if-then-else statement on one line

Question

I m just getting into Python and I really like the terseness of the syntax  However  is there an easier way of writing an if-then-else statement so it fits on one line   For example   if count    N      count   0 else      count   N   1   Is there a simpler way of writing this  I mean  in Objective-C I would write this as   count   count    N   0   count   1    Is there something similar for Python   Update  I know that in this instance I can use count     count   1    N    I m asking about the general syntax

User · Answer

lt execute-test-successful-condition gt  if  lt test gt  else  lt execute-test-fail-condition gt    with your code-snippet it would become   count   0 if count    N else N   1

User · Answer

count   0 if count    N else N 1   - the ternary operator  Although I d say your solution is more readable than this

User · Answer

That s more specifically a ternary operator expression than an if-then  here s the python syntax  value when true if condition else value when false   Better Example   thanks Mr  Burns    Yes  if fruit     Apple  else  No    Now with assignment and contrast with if syntax  fruit    Apple  isApple   True if fruit     Apple  else False   vs  fruit    Apple  isApple   False if fruit     Apple    isApple   True

User · Answer

Moreover  you can still use the  ordinary  if syntax and conflate it into one line with a colon   if i  gt  3  print  We are done      or  field plural   None if field plural is not None  print  insert into testtable plural    0    format field plural

User · Answer

General ternary syntax   value true if  lt test gt  else value false   Another way can be    value false  value true   lt test gt     e g   count    0 N 1  count  N    This evaluates both branches before choosing one  To only evaluate the chosen branch    lambda  value false  lambda  value true   lt test gt       e g    count    lambda 0  lambda N 1  count  N

[python] Putting a simple if-then-else statement on one line

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