I'm just getting into Python and I really like the terseness of the syntax. However, is there an easier way of writing an if-then-else statement so it fits on one line?
For example:
if count == N:
count = 0
else:
count = N + 1
Is there a simpler way of writing this? I mean, in Objective-C I would write this as:
count = count == N ? 0 : count + 1;
Is there something similar for Python?
Update
I know that in this instance I can use count == (count + 1) % N.
I'm asking about the general syntax.
This question is related to
python
if-statement
syntax
ternary-operator
<execute-test-successful-condition> if <test> else <execute-test-fail-condition>
with your code-snippet it would become,
count = 0 if count == N else N + 1
Moreover, you can still use the "ordinary" if syntax and conflate it into one line with a colon.
if i > 3: print("We are done.")
or
field_plural = None
if field_plural is not None: print("insert into testtable(plural) '{0}'".format(field_plural))
count = 0 if count == N else N+1
- the ternary operator. Although I'd say your solution is more readable than this.
General ternary syntax:
value_true if <test> else value_false
Another way can be:
[value_false, value_true][<test>]
e.g:
count = [0,N+1][count==N]
This evaluates both branches before choosing one. To only evaluate the chosen branch:
[lambda: value_false, lambda: value_true][<test>]()
e.g.:
count = [lambda:0, lambda:N+1][count==N]()
Source: Stackoverflow.com