[java] Round a double to 2 decimal places

If the value is 200.3456, it should be formatted to 200.34. If it is 200, then it should be 200.00.

If you really want the same double, but rounded in the way you want you can use BigDecimal, for example

new BigDecimal(myValue).setScale(2, RoundingMode.HALF_UP).doubleValue();

Please use Apache commons math:

Precision.round(10.4567, 2)

In your question, it seems that you want to avoid rounding the numbers as well? I think .format() will round the numbers using half-up, afaik?
so if you want to round, 200.3456 should be 200.35 for a precision of 2. but in your case, if you just want the first 2 and then discard the rest?

You could multiply it by 100 and then cast to an int (or taking the floor of the number), before dividing by 100 again.

200.3456 * 100 = 20034.56;  
(int) 20034.56 = 20034;  
20034/100.0 = 200.34;

You might have issues with really really big numbers close to the boundary though. In which case converting to a string and substring'ing it would work just as easily.

double d = 28786.079999999998;
String str = String.format("%1.2f", d);
d = Double.valueOf(str);

value = (int)(value * 100 + 0.5) / 100.0;

function Double round2(Double val) {
    return new BigDecimal(val.toString()).setScale(2,RoundingMode.HALF_UP).doubleValue();
}

Note the toString()!!!!

This is because BigDecimal converts the exact binary form of the double!!!

These are the various suggested methods and their fail cases.

// Always Good!
new BigDecimal(val.toString()).setScale(2,RoundingMode.HALF_UP).doubleValue() 

Double val = 260.775d; //EXPECTED 260.78
260.77 - WRONG - new BigDecimal(val).setScale(2,RoundingMode.HALF_UP).doubleValue()

Double val = 260.775d; //EXPECTED 260.78
260.77 - TRY AGAIN - Math.round(val * 100.d) / 100.0d  

Double val = 256.025d; //EXPECTED 256.03d
256.02 - OOPS - new DecimalFormat("0.00").format(val) 
// By default use half even, works if you change mode to half_up 

Double val = 256.025d; //EXPECTED 256.03d
256.02 - FAIL - (int)(val * 100 + 0.5) / 100.0;

For two rounding digits. Very simple and you are basically updating the variable instead of just display purposes which DecimalFormat does.

x = Math.floor(x * 100) / 100;

If you just want to print a double with two digits after the decimal point, use something like this:

double value = 200.3456;
System.out.printf("Value: %.2f", value);

If you want to have the result in a String instead of being printed to the console, use String.format() with the same arguments:

String result = String.format("%.2f", value);

Or use class DecimalFormat:

DecimalFormat df = new DecimalFormat("####0.00");
System.out.println("Value: " + df.format(value));

The easiest way, would be to do a trick like this;

double val = ....;
val = val*100;
val = Math.round(val);
val = val /100;

if val starts at 200.3456 then it goes to 20034.56 then it gets rounded to 20035 then we divide it to get 200.34.

if you wanted to always round down we could always truncate by casting to an int:

double val = ....;
val = val*100;
val = (double)((int) val);
val = val /100;

This technique will work for most cases because for very large doubles (positive or negative) it may overflow. but if you know that your values will be in an appropriate range then this should work for you.

Rounding a double is usually not what one wants. Instead, use String.format() to represent it in the desired format.

I think this is easier:

double time = 200.3456;
DecimalFormat df = new DecimalFormat("#.##");      
time = Double.valueOf(df.format(time));

System.out.println(time); // 200.35

Note that this will actually do the rounding for you, not just formatting.

double value= 200.3456;
DecimalFormat df = new DecimalFormat("0.00");      
System.out.println(df.format(value));