Django return redirect with parameters

Question

In my view function I want to call another view and pass data to it    return redirect  some-view-name   backend  form cleaned data      where backend is of registration backends object  and form cleaned data is a dict of form data  but both must be either sent as  args or   kwargs to prevent raising Don t mix  args and   kwargs in call to reverse    error   From what I ve found in the docs    def my view request               return redirect  some-view-name   foo  bar     It looks like I need to provide  some-view-name  argument  but is it just the name of the view function  or the name of the url   So I would like to make it similar to the way it s done in django-registration  where    to  args  kwargs   backend post registration redirect request  new user  return redirect to   args    kwargs   def post registration redirect self  request  user       return   registration complete             Ok so now  can I call directly my view function or do I need to provide a url for it   And what more important  how my funciotn call  and a url if needed  should look like   Both backend  and cleaned data are just passed through this view for a later usage  I ve tried this  but it s improper      url r  link     some-view-name     def some-view-name request   args     As well as this    return redirect  some url   backend backend  dataform cleaned data   url r  link     some-view-name      def some-view-name request  backend  data     still NoReverseMatch   But in django-registration  I ve seen something like this    url r  register    register   backend    registration backends default DefaultBackend    name  registration register     def register request  backend  success url None  form class None               disallowed url  registration disallowed                template name  user login logout register registration form html                extra context None

User · Answer

urls py            url r element update   P lt pk gt  d        element views element update   name  element update      views py   from django shortcuts import redirect from  models import Element   def element info request                 element   Element object get pk 1      return redirect  element update   pk element id   def element update request  pk

User · Answer

Firstly  your URL definition does not accept any parameters at all  If you want parameters to be passed from the URL into the view  you need to define them in the urlconf   Secondly  it s not at all clear what you are expecting to happen to the cleaned data dictionary  Don t forget you can t redirect to a POST - this is a limitation of HTTP  not Django - so your cleaned data either needs to be a URL parameter  horrible  or  slightly better  a series of GET parameters - so the URL would be in the form    link mybackend  field1 value1 amp field2 value2 amp field3 value3   and so on  In this case  field1  field2 and field3 are not included in the URLconf definition - they are available in the view via request GET   So your urlconf would be   url r  link   P lt backend gt  w        my function    and the view would look like   def my function request  backend      data   request GET   and the reverse would be  after importing urllib    return   s  s     redirect  my function   args  backend                       urllib urlencode form cleaned data     Edited after comment  The whole point of using redirect and reverse  as you have been doing  is that you go to the URL - it returns an Http code that causes the browser to redirect to the new URL  and call that   If you simply want to call the view from within your code  just do it directly - no need to use reverse at all   That said  if all you want to do is store the data  then just put it in the session   request session  temp data     form cleaned data

[python] Django return redirect() with parameters

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