I would like to make an image change after 30 seconds. The javascript I'm using looks like this:
var images = new Array();
images[0] = "image1.jpg";
images[1] = "image2.jpg";
images[2] = "image3.jpg";
setTimeout("changeImage()", 30000);
var x = 0;
function changeImage() {
document.getElementById("img").src=images[x];
x++;
}
HTML:
<img id="img" src="startpicture.jpg">
Now I haven't tested this one yet, but if my calculations are correct it will work :)
Now what I also want is to make a "fading transition" and I would like the changing of images to loop (it restarts after all the images have been shown).
Do any of you guys know how to do that?
This question is related to
javascript
html
image
loops
Just use That.Its Easy.
<script language="javascript" type="text/javascript">
var images = new Array()
images[0] = "img1.jpg";
images[1] = "img2.jpg";
images[2] = "img3.jpg";
setInterval("changeImage()", 30000);
var x=0;
function changeImage()
{
document.getElementById("img").src=images[x]
x++;
if (images.length == x)
{
x = 0;
}
}
</script>
And in Body Write this Code:-
<img id="img" src="imgstart.jpg">
setInterval function is the one that has to be used. Here is an example for the same without any fancy fading option. Simple Javascript that does an image change every 30 seconds. I have assumed that the images were kept in a separate images folder and hence _images/ is present at the beginning of every image. You can have your own path as required to be set.
CODE:
var im = document.getElementById("img");
var images = ["_images/image1.jpg","_images/image2.jpg","_images/image3.jpg"];
var index=0;
function changeImage()
{
im.setAttribute("src", images[index]);
index++;
if(index >= images.length)
{
index=0;
}
}
setInterval(changeImage, 30000);
You should take a look at various javascript libraries, they should be able to help you out:
All of them have tutorials, and fade in/fade out is a basic usage.
For e.g. in jQuery:
var $img = $("img"), i = 0, speed = 200;
window.setInterval(function() {
$img.fadeOut(speed, function() {
$img.attr("src", images[(++i % images.length)]);
$img.fadeIn(speed);
});
}, 30000);
Source: Stackoverflow.com