I want to toggle between CSS so when a user clicks the button (#user_button
) it shows the menu (#user_options
) and changes the CSS, and when the user clicks it again it goes back to normal. So far this is all I have:
$('#user_button').click( function() {
$('#user_options').toggle();
$("#user_button").css({
borderBottomLeftRadius: '0px',
borderBottomRightRadius: '0px'
});
return false;
});
Can anybody help?
The best option would be to set a class style in CSS like .showMenu
and .hideMenu
with the various styles inside. Then you can do something like
$("#user_button").addClass("showMenu");
You can do by maintaining the state as below:
$('#user_button').on('click',function(){
if($(this).attr('data-click-state') == 1) {
$(this).attr('data-click-state', 0);
$(this).css('background-color', 'red')
}
else {
$(this).attr('data-click-state', 1);
$(this).css('background-color', 'orange')
}
});
I would use the toggleClass function in jQuery and define the CSS to the class e.g.
/* start of css */
#user_button.active {
border-bottom-right-radius: 5px;
border-bottom-left-radius: 5px;
-webkit-border-bottom-right-radius: 5px; /* user-agent specific */
-webkit-border-bottom-left-radius: 5px;
-moz-border-radius-bottomright: 5px;
-moz-border-radius-bottomleft: 5px; /* etc... */
}
/* start of js */
$('#user_button').click(function() {
$('#user_options').toggle();
$(this).toggleClass('active');
return false;
})
You might want to use jQuery's .addClass and .removeClass commands, and create two different classes for the states. This, to me, would be the best practice way of doing it.
The initiale code must have borderBottomLeftRadius: 0px
$('#user_button').toggle().css('borderBottomLeftRadius','+5px');
Source: Stackoverflow.com