Consider the case x = n**(1.0/m), where n=10**5, m=5. In Python, x will be 10.000000000000002, which is only not integer because of floating point arithmetic operations.
So I'd check
if str(float(x)).endswith('.0'): print "It's an integer."
I've tested it with this code:
for a in range(2,100):
for b in range(2,100):
x = (a**b)**(1.0/b)
print a,b, x, str(float(x)).endswith('.0')
It outputs True for all a and b.