[python] How do you replace all the occurrences of a certain character in a string?

I am reading a csv into a:

import csv
import collections
import pdb
import math
import urllib

def do_work():
  a=get_file('c:/pythonwork/cds/cds.csv')
  a=remove_chars(a)
  print a[0:10]

def get_file(start_file): #opens original file, reads it to array
  with open(start_file,'rb') as f:
    data=list(csv.reader(f))
  return (data)

def remove_chars(a):
  badchars=['a','b','c','d']
  for row in a:
    for letter in badchars:
      row[8].replace(letter,'')
  return a

I would like to replace all occurrences of ['a','b','c','d'] in the 8th element of the line with empty string. the remove_chars function is not working.

Is there a better way to do this?

This question is related to python csv

The answer is


The problem is you're not doing anything with the result of replace. In Python strings are immutable so anything that manipulates a string returns a new string instead of modifying the original string.

line[8] = line[8].replace(letter, "")

I would use the translate method without translation table. It deletes the letters in second argument in recent Python versions.

def remove_chars(line):
    line7=line[7].translate(None,'abcd')
    return line[:7]+[line7]+line[8:]

line= ['ad','da','sdf','asd',
        '3424','342sfas','asdfaf','sdfa',
        'afase']
print line[7]
line = remove_chars(line)
print line[7]

You really should have multiple input, e.g. one for firstname, middle names, lastname and another one for age. If you want to have some fun though you could try:

>>> input_given="join smith 25"
>>> chars="".join([i for i in input_given if not i.isdigit()])
>>> age=input_given.translate(None,chars)
>>> age
'25'
>>> name=input_given.replace(age,"").strip()
>>> name
'join smith'

This would of course fail if there is multiple numbers in the input. a quick check would be:

assert(age in input_given)

and also:

assert(len(name)<len(input_given))