Like this:
void * p = (void *)0x28ff44;
Or if you want it as a char *:
char * p = (char *)0x28ff44;
...etc.
If you're pointing to something you really, really aren't meant to change, add a const:
const void * p = (const void *)0x28ff44;
const char * p = (const char *)0x28ff44;
...since I figure this must be some kind of "well-known address" and those are typically (though by no means always) read-only.
int *p=(int *)0x1234 = 10; //0x1234 is the memory address and value 10 is assigned in that address
unsigned int *ptr=(unsigned int *)0x903jf = 20;//0x903j is memory address and value 20 is assigned
Basically in Embedded platform we are using directly addresses instead of names
Your code would be like this:
int *p = (int *)0x28ff44;
int needs to be the type of the object that you are referencing or it can be void.
But be careful so that you don't try to access something that doesn't belong to your program.
let's say you want a pointer to point at the address 0x28ff4402, the usual way is
uint32_t *ptr;
ptr = (uint32_t*) 0x28ff4402 //type-casting the address value to uint32_t pointer
*ptr |= (1<<13) | (1<<10); //access the address how ever you want
So the short way is to use a MACRO,
#define ptr *(uint32_t *) (0x28ff4402)
Source: Stackoverflow.com