lvalue required as left operand of assignment error when using C

Question

int main         int x 3   4 5 6      int  p x     p  1 p   compiler shows error saying              lvalue required as left               operand of assignment      cout lt  lt p 1     getch

User · Answer

Put simply  an lvalue is something that can appear on the left-hand side of an assignment  typically a variable or array element     So if you define int  p  then p is an lvalue   p 1  which is a valid expression  is not an lvalue   If you re trying to add 1 to p  the correct syntax is   p   p   1

User · Answer

To assign  you should use p p 1  instead of p 1 p   int main         int x 3   4 5 6      int  p x     p p 1    You just needed to switch the terms around      cout lt  lt p lt  lt endl     getch

User · Answer

if you use an assignment operator but use it in wrong way or in wrong place   then you ll get this types of errors   suppose if you type  p 1 p  you will get the error    you will get the same error for this  if ch   a   amp  amp  ch  z   as you see can see that I i tried to assign in if   statement    how silly I am    right   ha ha  actually i forgot to give less then  lt   sign  if ch   a   amp  amp  ch lt   z   and got the error

User · Answer

When you have an assignment operator in a statement  the LHS of the operator must be something the language calls an lvalue  If the LHS of the operator does not evaluate to an lvalue  the value from the RHS cannot be assigned to the LHS   You cannot use   10   20    since 10 does not evaluate to an lvalue   You can use   int i  i   20    since i does evaluate to an lvalue   You cannot use   int i  i   1   20    since i   1 does not evaluate to an lvalue   In your case  p   1 does not evaluate to an lavalue  Hence  you cannot use  p   1   p

User · Answer

It is just a typo I guess -  p  1    instead of p  1 p  is required    As name suggest lvalue expression should be left-hand operand of the assignment operator

[c++] lvalue required as left operand of assignment error when using C++

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