[python] OpenCV & Python - Image too big to display

I have an image that is 6400 × 3200, while my screen is 1280 x 800. Therefore, the image needs to be resized for display only. I am using Python and OpenCV 2.4.9. According to OpenCV Documentation,

If you need to show an image that is bigger than the screen resolution, you will need to call namedWindow("", WINDOW_NORMAL) before the imshow.

That is what I am doing, but the image is not fitted to the screen, only a portion is shown because it's too big. I've also tried with cv2.resizeWindow, but it doesn't make any difference.

import cv2
cv2.namedWindow("output", cv2.WINDOW_NORMAL)        # Create window with freedom of dimensions
# cv2.resizeWindow("output", 400, 300)              # Resize window to specified dimensions
im = cv2.imread("earth.jpg")                        # Read image
cv2.imshow("output", im)                            # Show image
cv2.waitKey(0)                                      # Display the image infinitely until any keypress

This question is related to python image opencv image-processing imshow

The answer is

Try with this code:

from PIL import Image


Try this:

image = cv2.imread("img/Demo.jpg")
image = cv2.resize(image,(240,240))

The image is now resized. Displaying it will render in 240x240.

Use this for example:

cv2.namedWindow('finalImg', cv2.WINDOW_NORMAL)

Looks like opencv lib is pretty sensitive to parameters passed to the methods. The following code worked for me using opencv 4.3.0:

win_name = "visualization"  #  1. use var to specify window name everywhere
cv2.namedWindow(win_name, cv2.WINDOW_NORMAL)  #  2. use 'normal' flag
img = cv2.imread(filename)
h,w = img.shape[:2]  #  suits for image containing any amount of channels
h = int(h / resize_factor)  #  one must compute beforehand
w = int(w / resize_factor)  #  and convert to INT
cv2.resizeWindow(win_name, w, h)  #  use variables defined/computed BEFOREHAND
cv2.imshow(win_name, img)

The other answers perform a fixed (width, height) resize. If you wanted to resize to a specific size while maintaining aspect ratio, use this

def ResizeWithAspectRatio(image, width=None, height=None, inter=cv2.INTER_AREA):
    dim = None
    (h, w) = image.shape[:2]

    if width is None and height is None:
        return image
    if width is None:
        r = height / float(h)
        dim = (int(w * r), height)
        r = width / float(w)
        dim = (width, int(h * r))

    return cv2.resize(image, dim, interpolation=inter)


image = cv2.imread('img.png')
resize = ResizeWithAspectRatio(image, width=1280) # Resize by width OR
# resize = ResizeWithAspectRatio(image, height=1280) # Resize by height 

cv2.imshow('resize', resize)

In opencv, cv.namedWindow() just creates a window object as you determine, but not resizing the original image. You can use cv2.resize(img, resolution) to solve the problem.

Here's what it displays, a 740 * 411 resolution image. The original image

image = cv2.imread("740*411.jpg")
cv2.imshow("image", image)

Here, it displays a 100 * 200 resolution image after resizing. Remember the resolution parameter use column first then is row.

Image after resizing

image = cv2.imread("740*411.jpg")
image = cv2.resize(image, (200, 100))
cv2.imshow("image", image)

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