[bash] How to check if a symlink exists

I'm trying to check if a symlink exists in bash. Here's what I've tried.

mda=/usr/mda
if [ ! -L $mda ]; then
  echo "=> File doesn't exist"
fi


mda='/usr/mda'
if [ ! -L $mda ]; then
  echo "=> File doesn't exist"
fi

However, that doesn't work. If '!' is left out, it never triggers. And if '!' is there, it triggers every time.

Maybe this is what you are looking for. To check if a file exist and is not a link.

Try this command:

file="/usr/mda" 
[ -f $file ] && [ ! -L $file ] && echo "$file exists and is not a symlink"

How about using readlink?

# if symlink, readlink returns not empty string (the symlink target)
# if string is not empty, test exits w/ 0 (normal)
#
# if non symlink, readlink returns empty string
# if string is empty, test exits w/ 1 (error)
simlink? () {
  test "$(readlink "${1}")";
}

FILE=/usr/mda

if simlink? "${FILE}"; then
  echo $FILE is a symlink
else
  echo $FILE is not a symlink
fi

1. first you can do with this style:

   mda="/usr/mda"
   if [ ! -L "${mda}" ]; then
     echo "=> File doesn't exist"
   fi
   

2. if you want to do it in more advanced style you can write it like below:

   #!/bin/bash
   mda="$1"
   if [ -e "$1" ]; then
       if [ ! -L "$1" ]
       then
           echo "you entry is not symlink"
       else
           echo "your entry is symlink"
       fi
   else
     echo "=> File doesn't exist"
   fi
   

the result of above is like:

root@linux:~# ./sym.sh /etc/passwd
you entry is not symlink
root@linux:~# ./sym.sh /usr/mda 
your entry is symlink
root@linux:~# ./sym.sh 
=> File doesn't exist

You can check the existence of a symlink and that it is not broken with:

[ -L ${my_link} ] && [ -e ${my_link} ]

So, the complete solution is:

if [ -L ${my_link} ] ; then
   if [ -e ${my_link} ] ; then
      echo "Good link"
   else
      echo "Broken link"
   fi
elif [ -e ${my_link} ] ; then
   echo "Not a link"
else
   echo "Missing"
fi

-L tests whether there is a symlink, broken or not. By combining with -e you can test whether the link is valid (links to a directory or file), not just whether it exists.

-L is the test for file exists and is also a symbolic link

If you do not want to test for the file being a symbolic link, but just test to see if it exists regardless of type (file, directory, socket etc) then use -e

So if file is really file and not just a symbolic link you can do all these tests and get an exit status whose value indicates the error condition.

if [ ! \( -e "${file}" \) ]
then
     echo "%ERROR: file ${file} does not exist!" >&2
     exit 1
elif [ ! \( -f "${file}" \) ]
then
     echo "%ERROR: ${file} is not a file!" >&2
     exit 2
elif [ ! \( -r "${file}" \) ]
then
     echo "%ERROR: file ${file} is not readable!" >&2
     exit 3
elif [ ! \( -s "${file}" \) ]
then
     echo "%ERROR: file ${file} is empty!" >&2
     exit 4
fi

Is the file really a symbolic link? If not, the usual test for existence is -r or -e.

See man test.

If you are testing for file existence you want -e not -L. -L tests for a symlink.