I'm trying to pass a URL as a url parameter in php but when I try to get this parameter I get nothing
I'm using the following url form:
http://localhost/dispatch.php?link=www.google.com
I'm trying to get it through:
$_GET['link'];
But nothing returned. What is the problem?
As Alvaro said, $_GET is not a function but an array containing the parameters So you can retrieve one element from that array using
<?php
$link = $_GET['link'];
echo $link;
?>
Expected OP:
www.google.com
$Query_String = explode("&", explode("?", $_SERVER['REQUEST_URI'])[1] );
var_dump($Query_String)
Array ( [ 0] => link=www.google.com )
To make sure you're always on the safe side, without getting all kinds of unwanted code insertion use FILTERS:
echo filter_input(INPUT_GET,"link",FILTER_SANITIZE_STRING);
More reading on php.net function filter_input, or check out the description of the different filters
Whomever gets nothing back, I think he just has to enclose the result in html tags,
Like this:
<html>
<head></head>
<body>
<?php
echo $_GET['link'];
?>
<body>
</html>
The accepted answer is good. But if you have a scenario like this:
http://www.mydomain.me/index.php?state=California.php#Berkeley
You can treat the named anchor as a query string like this:
http://www.mydomain.me/index.php?state=California.php&city=Berkeley
Then, access it like this:
$Url = $_GET['state']."#".$_GET['city'];
I was getting nothing for any $_GET["..."] (e.g print_r($_GET) gave an empty array) yet $_SERVER['REQUEST_URI'] showed stuff should be there. In the end it turned out that I was only getting to the web page because my .htaccess was redirecting it there (my 404 handler was the same .php file, and I had made a typo in the browser when testing).
Simply changing the name meant the same php code worked once the 404 redirection wasn't kicking in!
So there are ways $_GET can return nothing even though the php code may be correct.
Please post your code,
<?php
echo $_GET['link'];
?>
or
<?php
echo $_REQUEST['link'];
?>
do work...
Use this:
$parameter = $_SERVER['QUERY_STRING'];
echo $parameter;
Or just use:
$parameter = $_GET['link'];
echo $parameter ;
Source: Stackoverflow.com