How to remove all whitespace from a string

Question

So   xx yy 11 22  33   will become  xxyy112233   How can I achieve this

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Please note that soultions written above removes only space  If you want also to remove tab or new line use stri replace all charclass from stringi package   library stringi  stri replace all charclass     ala  t  ma  n kota        p WHITE SPACE            1   alamakota

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x    xx yy 11 22 33   gsub          x    gt   1   xxyy112233

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This way you can remove all spaces from all character variables in your data frame  If you would prefer to choose only some of the variables  use mutateor mutate at    library dplyr  library stringr   remove all ws lt - function string       return gsub          str squish string       df lt -df   gt    mutate if is character  remove all ws

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I just learned about the  stringr  package to remove white space from the beginning and end of a string with str trim    side  both   but it also has a replacement function so that   a  lt -   xx yy 11 22 33    str replace all string a  pattern      repl       1   xxyy112233

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Another approach can be taken into account library stringr  str replace all  quot  xx yy 11 22  33  quot   regex  quot   s  quot     quot  quot      1   quot xxyy112233 quot     s  Matches Space  tab  vertical tab  newline  form feed  carriage return    Matches at least 0 times

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In general  we want a solution that is vectorised  so here s a better test example   whitespace  lt -    t n r v f    space  tab  newline                                 carriage return  vertical tab  form feed x  lt - c      x y                spaces before  after and in between      u2190  u2192      contains unicode chars   paste0               varied whitespace          whitespace        x        whitespace        y        whitespace       collapse                NA                   missing       1    x y                                  2                                         3     t n r v fx  t n r v fy  t n r v f      4  NA     The base R approach  gsub  gsub replaces all instances of a string  fixed   TRUE  or regular expression  fixed   FALSE  the default  with another string   To remove all spaces  use   gsub          x  fixed   TRUE      1   xy                                                   3    t n r v fx t n r v fy t n r v f  NA    As DWin noted  in this case fixed   TRUE isn t necessary but provides slightly better performance since matching a fixed string is faster than matching a regular expression   If you want to remove all types of whitespace  use   gsub     space          x    note the double square brackets     1   xy        xy  NA   gsub    s       x            same  note the double backslash  library regex  gsub space        x          same      space    is an R-specific regular expression group matching all space characters    s is a language-independent regular-expression that does the same thing     The stringr approach  str replace all and str trim  stringr provides more human-readable wrappers around the base R functions  though as of Dec 2014  the development version has a branch built on top of stringi  mentioned below    The equivalents of the above commands  using  str replace all  3   are   library stringr  str replace all x  fixed           str replace all x  space          stringr also has a str trim function which removes only leading and trailing whitespace   str trim x       1   x y                           x  t n r v fy  NA     str trim x   left           1   x y                                    3   x  t n r v fy  t n r v f  NA      str trim x   right           1    x y                                   3     t n r v fx  t n r v fy  NA           The stringi approach  stri replace all charclass and stri trim  stringi is built upon the platform-independent ICU library  and has an extensive set of string manipulation functions   The equivalents of the above are   library stringi  stri replace all fixed x           stri replace all charclass x     p WHITE SPACE          Here    p WHITE SPACE   is an alternate syntax for the set of Unicode code points considered to be whitespace  equivalent to     space         s  and space     For more complex regular expression replacements  there is also stri replace all regex   stringi also has trim functions   stri trim x  stri trim both x       same stri trim x   left   stri trim left x       same stri trim x   right     stri trim right x      same

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The function str squish   from package stringr of tidyverse does the magic   library dplyr  library stringr   df  lt - data frame a   c    aZe  aze s    wxc  s     aze                         b   c    12    12     34e e4                        stringsAsFactors   FALSE  df  lt - df   gt     rowwise     gt     mutate all funs str squish        gt     ungroup   df    A tibble  2 x 2   a         b         lt chr gt       lt chr gt   1 aZe aze s 12 12  2 wxc s aze 34e e4

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From stringr library you could try this    Remove consecutive fill blanks Remove fill blank  library stringr               2          1                                       V          V      str replace all str trim   xx yy 11 22  33

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Use    blank    to match any kind of horizontal white space characters   gsub     blank            xx yy 11 22  33       1   xxyy112233

[r] How to remove all whitespace from a string?

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