Making a list of evenly spaced numbers in a certain range in python

Question

What is a pythonic way of making list of arbitrary length containing evenly spaced numbers  not just whole integers  between given bounds  For instance   my func 0 5 10      lower bound   upper bound   length       0  0 5  1  1 5  2  2 5  3  3 5  4  4 5      Note the Range   function only deals with integers  And this   def my func low up leng       list          step    up - low    float leng      for i in range leng           list append low          low   low   step     return list   seems too complicated  Any ideas

User · Answer

f   0 5 a   0 b   9 d    x   f for x in range a  b     would be a way to do it

User · Answer

Similar to unutbu s answer  you can use numpy s arange function  which is analog to Python s intrinsic function range  Notice that the end point is not included  as in range    gt  gt  gt  import numpy as np  gt  gt  gt  a   np arange 0 5  0 5   gt  gt  gt  a array   0     0 5   1     1 5   2     2 5   3     3 5   4     4 5    gt  gt  gt  a   np arange 0 5  0 5    returns a numpy array  gt  gt  gt  a array   0     0 5   1     1 5   2     2 5   3     3 5   4     4 5    gt  gt  gt  a tolist     if you prefer it as a list  0 0  0 5  1 0  1 5  2 0  2 5  3 0  3 5  4 0  4 5

User · Answer

Similar to Howard s answer but a bit more efficient   def my func low  up  leng       step     up-low    1 0   leng      return  low i step for i in xrange leng

User · Answer

You can use the following approach    lower   x  upper-lower  length for x in range length     lower and or upper must be assigned as floats for this approach to work

User · Answer

Numpy s r  convenience function can also create evenly spaced lists with syntax np r  start stop steps   If steps is a real number  ending on j   then the end point is included  equivalent to np linspace start  stop  step  endpoint 1   otherwise not    gt  gt  gt  np r  -1 1 6j   0  3  5  6  array  -1    -0 6  -0 2   0 2   0 6   1      You can also directly concatente other arrays and also scalars    gt  gt  gt  np r  -1 1 6j   0  3  5  6  array  -1    -0 6  -0 2   0 2   0 6   1     0     0     0     5     6

User · Answer

Given numpy  you could use linspace   Including the right endpoint  5    In  46   import numpy as np In  47   np linspace 0 5 10  Out 47    array   0            0 55555556   1 11111111   1 66666667   2 22222222          2 77777778   3 33333333   3 88888889   4 44444444   5              Excluding the right endpoint   In  48   np linspace 0 5 10 endpoint False  Out 48   array   0     0 5   1     1 5   2     2 5   3     3 5   4     4 5

User · Answer

You can use the folowing code   def float range initVal  itemCount  step       for x in xrange itemCount           yield initVal         initVal    step   x for x in float range 1  3  0 1

[list] Making a list of evenly spaced numbers in a certain range in python

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