How to calculate date difference in JavaScript

Question

I want to calculate date difference in days  hours  minutes  seconds  milliseconds  nanoseconds  How can I do it

User · Answer

Sorry but flat millisecond calculation is not reliable Thanks for all the responses  but few of the functions I tried are failing either on  1  A date near today s date  2  A date in 1970 or  3  A date in a leap year    Approach that best worked for me and covers all scenario e g  leap year  near date in 1970  feb 29 etc   var someday   new Date  8 1 1985    var today   new Date    var years   today getFullYear   - someday getFullYear        Reset someday to the current year  someday setFullYear today getFullYear         Depending on when that day falls for this year  subtract 1  if  today  lt  someday        years--    document write  Its been     years     full years

User · Answer

Expressions like  difference in days  are never as simple as they seem  If you have the following dates   d1  2011-10-15 23 59 00 d1  2011-10-16 00 01 00   the difference in time is 2 minutes  should the  difference in days  be 1 or 0  Similar issues arise for any expression of the difference in months  years or whatever since years  months and days are of different lengths and different times  e g  the day that daylight saving starts is 1 hour shorter than usual and two hours shorter than the day that it ends    Here is a function for a difference in days that ignores the time  i e  for the above dates it returns 1         Get the number of days between two dates - not inclusive       between  does not include the start date  so days    between Thursday and Friday is one  Thursday to Saturday    is two  and so on  Between Friday and the following Friday is 7      e g  getDaysBetweenDates  22-Jul-2011  29-jul-2011    gt  7      If want inclusive dates  e g  leave from 1 1 2011 to 30 1 2011      use date prior to start date  i e  31 12 2010 to 30 1 2011       Only calculates whole days      Assumes d0  lt   d1    function getDaysBetweenDates d0  d1       var msPerDay   8 64e7        Copy dates so don t mess them up   var x0   new Date d0     var x1   new Date d1         Set to noon - avoid DST errors   x0 setHours 12 0 0     x1 setHours 12 0 0         Round to remove daylight saving errors   return Math round   x1 - x0    msPerDay        This can be more concise    x000D   x000D      Return number of days between d0 and d1  x000D      Returns positive if d0  lt  d1  otherwise negative  x000D     x000D      e g  between 2000-02-28 and 2001-02-28 there are 366 days x000D           between 2015-12-28 and 2015-12-29 there is 1 day x000D           between 2015-12-28 23 59 59 and 2015-12-29 00 00 01 there is 1 day x000D           between 2015-12-28 00 00 01 and 2015-12-28 23 59 59 there are 0 days x000D             x000D       param  Date  d0  - start date x000D       param  Date  d1  - end date x000D       returns  number  - whole number of days between d0 and d1 x000D     x000D     x000D  function daysDifference d0  d1    x000D    var diff   new Date  d1  setHours 12  - new Date  d0  setHours 12   x000D    return Math round diff 8 64e7   x000D    x000D   x000D     Simple formatter x000D  function formatDate date   x000D    return  date getFullYear     0   date getMonth   1   slice -2    0  date getDate    slice -2   join  -    x000D    x000D   x000D     Examples x000D    new Date 2000 1 28   new Date 2001 1 28        Leap year x000D    new Date 2001 1 28   new Date 2002 1 28        Not leap year x000D    new Date 2017 0 1    new Date 2017 1 1    x000D    forEach function dates    x000D    document write  From     formatDate dates 0       to     formatDate dates 1     x000D                     is     daysDifference dates 0  dates 1       days lt br gt     x000D      x000D   x000D   x000D

User · Answer

lt html lang  en  gt   lt head gt   lt script gt  function getDateDiff time1  time2      var str1  time1 split         var str2  time2 split                            yyyy     mm         dd   var t1   new Date str1 2   str1 0 -1  str1 1      var t2   new Date str2 2   str2 0 -1  str2 1       var diffMS   t1 - t2        console log diffMS     ms       var diffS   diffMS   1000        console log diffS            var diffM   diffS   60    console log diffM     minutes       var diffH   diffM   60    console log diffH     hours       var diffD   diffH   24    console log diffD     days      alert diffD        alert getDateDiff  10 18 2013   10 14 2013      lt  script gt   lt  head gt   lt body gt     lt input type  button          onclick  getDateDiff  10 18 2013   10 14 2013            value  clickHere      gt    lt  body gt   lt  html gt

User · Answer

Another solution is convert difference to a new Date object and get that date s year diff from 1970   month  day etc   var date1   new Date 2010  6  17   var date2   new Date 2013  12  18   var diff   new Date date2 getTime   - date1 getTime        diff is  Thu Jul 05 1973 04 00 00 GMT 0300  EEST   console log diff getUTCFullYear   - 1970      Gives difference as year    3  console log diff getUTCMonth        Gives month count of difference    6  console log diff getUTCDate   - 1      Gives day count of difference    4   So difference is like  3 years and 6 months and 4 days   If you want to take difference in a human readable style  that can help you

User · Answer

use Moment js for all your JavaScript related date-time calculation  Answer to your question is   var a   moment  2007  0  29       var b   moment  2007  0  28        a diff b     86400000     Complete details can be found here

User · Answer

Assuming you have two Date objects  you can just subtract them to get the difference in milliseconds  var difference   date2 - date1   From there  you can use simple arithmetic to derive the other values

User · Answer

If you are using moment js then it is pretty simple to find date difference   var now     04 09 2013 15 00 00   var then    04 09 2013 14 20 30    moment utc moment now  DD MM YYYY HH mm ss   diff moment then  DD MM YYYY HH mm ss     format  HH mm ss

User · Answer

With momentjs it s simple   moment  2016-04-08   fromNow

User · Answer

function DateDiff date1  date2        date1 setHours 0       date1 setMinutes 0  0  0       date2 setHours 0       date2 setMinutes 0  0  0       var datediff   Math abs date1 getTime   - date2 getTime        difference      return parseInt datediff    24   60   60   1000   10     Convert values days and return value

User · Answer

Ok  there are a bunch of ways you can do that  Yes  you can use plain old JS  Just try  let dt1   new Date   let dt2   new Date    Let s emulate passage using Date prototype setMinutes and make sure we are in range  dt1 setMinutes 7  dt2 setMinutes 42  console log  Elapsed seconds    dt2-dt1  1000   Alternatively you could use some library like js-joda  where you can easily do things like this  directly from docs   var dt1   LocalDateTime parse  quot 2016-02-26T23 55 42 123 quot    var dt2   dt1    plusYears 6     plusMonths 12     plusHours 2     plusMinutes 42     plusSeconds 12       obtain the duration between the two dates dt1 until dt2  ChronoUnit YEARS      7 dt1 until dt2  ChronoUnit MONTHS      84 dt1 until dt2  ChronoUnit WEEKS      356 dt1 until dt2  ChronoUnit DAYS      2557 dt1 until dt2  ChronoUnit HOURS      61370 dt1 until dt2  ChronoUnit MINUTES      3682242 dt1 until dt2  ChronoUnit SECONDS      220934532  There are plenty more libraries ofc  but js-joda has an added bonus of being available also in Java  where it has been extensively tested  All those tests have been migrated to js-joda  it s also immutable

User · Answer

var d1 new Date 2011 0 1      jan 1 2011 var d2 new Date       now  var diff d2-d1 sign diff lt 0 -1 1 milliseconds seconds minutes hours days  diff  sign     or diff Math abs diff   diff  diff- milliseconds diff 1000   1000  diff  diff- seconds diff 60   60  diff  diff- minutes diff 60   60  days  diff- hours diff 24   24   console info sign   1  Elapsed     Remains                  days   days                  hours   hours                  minutes   minutes                  seconds   seconds                  milliseconds   milliseconds

User · Answer

var DateDiff          inDays  function d1  d2            var t2   d2 getTime            var t1   d1 getTime             return parseInt  t2-t1   24 3600 1000                inWeeks  function d1  d2            var t2   d2 getTime            var t1   d1 getTime             return parseInt  t2-t1   24 3600 1000 7                inMonths  function d1  d2            var d1Y   d1 getFullYear            var d2Y   d2 getFullYear            var d1M   d1 getMonth            var d2M   d2 getMonth             return  d2M 12 d2Y - d1M 12 d1Y               inYears  function d1  d2            return d2 getFullYear  -d1 getFullYear             var dString    May  20  1984    var d1   new Date dString   var d2   new Date     document write   lt br   gt Number of  lt b gt days lt  b gt  since   dString      DateDiff inDays d1  d2    document write   lt br   gt Number of  lt b gt weeks lt  b gt  since   dString      DateDiff inWeeks d1  d2    document write   lt br   gt Number of  lt b gt months lt  b gt  since   dString      DateDiff inMonths d1  d2    document write   lt br   gt Number of  lt b gt years lt  b gt  since   dString      DateDiff inYears d1  d2      Code sample taken from here

User · Answer

x000D   x000D  function daysInMonth  month  year    x000D      return new Date year  month  0  getDate    x000D    x000D  function getduration    x000D   x000D  let A  document getElementById  date1 id   value x000D  let B  document getElementById  date2 id   value x000D   x000D  let C Number A substring 3 5   x000D  let D Number B substring 3 5   x000D  let dif D-C x000D  let arr     x000D  let sum 0  x000D  for  let i 0 i lt dif 1 i     x000D    sum  Number daysInMonth i C 2019   x000D    x000D  let sum alter 0  x000D  for  let i 0 i lt dif i     x000D    sum alter  Number daysInMonth i C 2019   x000D    x000D  let no of month  Number B substring 3 5   - Number A substring 3 5    x000D  let days     x000D  if   Number B substring 3 5   - Number A substring 3 5    gt 0  Number B substring 0 2   - Number A substring 0 2   lt 0   x000D  days Number B substring 0 2   - Number A substring 0 2     sum alter x000D    x000D   x000D  if   Number B substring 3 5      Number A substring 3 5      x000D  console log Number B substring 0 2   - Number A substring 0 2     sum alter  x000D    x000D   x000D  time 1     time 2     let hour     x000D   time 1 document getElementById  time1 id   value x000D   time 2 document getElementById  time2 id   value x000D    if  time 1 substring 0 2    12    x000D       time 1  00 00 00 PM  x000D      x000D  if  time 1 substring 9 11   time 2 substring 9 11    x000D  hour Math abs Number time 2 substring 0 2   - Number time 1 substring 0 2    x000D    x000D  if  time 1 substring 9 11   time 2 substring 9 11    x000D  hour Math abs Number time 2 substring 0 2   - Number time 1 substring 0 2    12 x000D    x000D  let min Math abs Number time 1 substring 3 5  -Number time 2 substring 3 5    x000D  document getElementById  duration id   value days    days    hour    hour     min    min    x000D    x000D   lt input type  text  id  date1 id  placeholder  28 05 2019  gt  x000D   lt input type  text  id  date2 id  placeholder  29 06 2019  gt  x000D   lt br gt  lt br gt  x000D   lt input type  text  id  time1 id  placeholder  08 01 00 AM  gt  x000D   lt input type  text  id  time2 id  placeholder  00 00 00 PM  gt  x000D   lt br gt  lt br gt  x000D   lt button class  text  onClick  getduration    gt Submit  lt  button gt  x000D   lt br gt  lt br gt  x000D   lt input type  text  id  duration id  placeholder  days hour min  gt  x000D   x000D   x000D

User · Answer

This is how you can implement difference between dates without a framework   function getDateDiff dateOne  dateTwo            if dateOne charAt 2    -   amp  dateTwo charAt 2    -                dateOne   new Date formatDate dateOne                dateTwo   new Date formatDate dateTwo                      else              dateOne   new Date dateOne               dateTwo   new Date dateTwo                                 let timeDiff   Math abs dateOne getTime   - dateTwo getTime             let diffDays   Math ceil timeDiff    1000   3600   24            let diffMonths   Math ceil diffDays 31           let diffYears   Math ceil diffMonths 12            let message    Difference in Days      diffDays                                Difference in Months      diffMonths                                Difference in Years      diffYears          return message              function formatDate date             return date split  -   reverse   join  -               console log getDateDiff  23-04-2017    23-04-2018

User · Answer

this should work just fine if you just need to show what time left  since JavaScript uses frames for its time you ll have get your End Time - The Time RN after that we can divide it by 1000 since apparently 1000 frames   1 seconds  after that you can use the basic math of time  but there s still a problem to this code  since the calculation is static  it can t compensate for the different day total in a year  360 365 366   the bunch of IF after the calculation is to make it null if the time is lower than 0  hope this helps even though it s not exactly what you re asking     var now   new Date    var end   new Date  End Time    var total    end - now    var totalD    Math abs Math floor total 1000     var years   Math floor totalD    365 60 60 24    var months   Math floor  totalD - years 365 60 60 24     30 60 60 24    var days   Math floor  totalD - years 365 60 60 24 - months 30 60 60 24    60 60 24    var hours   Math floor  totalD - years 365 60 60 24 - months 30 60 60 24 - days 60 60 24    60 60    var minutes   Math floor  totalD - years 365 60 60 24 - months 30 60 60 24 - days 60 60 24 - hours 60 60    60    var seconds   Math floor totalD - years 365 60 60 24 - months 30 60 60 24 - days 60 60 24 - hours 60 60 - minutes 60    var Y   years  lt  1        years     Years    var M   months  lt  1        months     Months    var D   days  lt  1        days     Days    var H   hours  lt  1        hours     Hours    var I   minutes  lt  1        minutes     Minutes    var S   seconds  lt  1        seconds     Seconds    var A   years    0  amp  amp  months    0  amp  amp  days    0  amp  amp  hours    0  amp  amp  minutes    0  amp  amp  seconds    0    Sending      Remaining    document getElementById  txt   innerHTML   Y   M   D   H   I   S   A

User · Answer

function DateDiff b  e        let         endYear   e getFullYear            endMonth   e getMonth            years   endYear - b getFullYear            months   endMonth - b getMonth            days   e getDate   - b getDate        if  months  lt  0                years--          months    12            if  days  lt  0                months--          days    new Date endYear  endMonth  0  getDate              return  years  months  days       years  months  days    DateDiff      new Date  October 21  1980        new Date  July 11  2017        36 8 20

User · Answer

I think this should do it   let today   new Date    let form date new Date  2019-10-23   let difference form date gt today   form date-today   today-form date let diff days Math floor difference  1000 3600 24

User · Answer

based on javascript runtime prototype implementation you can use simple arithmetic to subtract dates as in bellow var sep   new Date 2020  07  31  23  59  59   var today   new Date    var diffD   Math floor  sep - today     1000   60   60   24    console log  Day Diff    diffD    the difference return answer as milliseconds  then you have to convert it by division   by 1000 to convert to second by 1000  60 convert to minute by 1000  60  60 convert to hour by 1000  60  60  24 convert to day

[javascript] How to calculate date difference in JavaScript?

Examples related to javascript

Examples related to datetime