How to obtain the last index of a list

Question

Suppose I ve the following list   list1    1  2  33  51                                              indices  0  1   2   3   How do I obtain the last index  which in this case would be 3  of that list

User · Answer

Did you mean len list1 -1   If you re searching for other method  you can try list1 index list1 -1    but I don t recommend this one  You will have to be sure  that the list contains NO duplicates

User · Answer

len list1 -1 is definitely the way to go  but if you absolutely need a list that has a function that returns the last index  you could create a class that inherits from list   class MyList list       def last index self           return len self -1    gt  gt  gt  l MyList  1  2  33  51    gt  gt  gt  l last index   3

User · Answer

a     1    2    3    4   print len a  - 1 3

User · Answer

I guess you want  last index   len list1  - 1    which would store 3 in last index

User · Answer

all above answers is correct but however a       len list1  - 1   where 0 - 1   -1  to be more precisely a       index   len a  - 1 if a else None   if index    None   raise Exception  quot Empty Array quot    since arrays is starting with 0

User · Answer

You can use the list length  The last index will be the length of the list minus one   len list1 -1    3

User · Answer

the best and fast way to obtain last index of a list is using -1 for number of index   for example   my list    0  1   test   2   hi   print my list -1     out put is    hi   index -1 in show you last index or first index of the end

[python] How to obtain the last index of a list?

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