Try
String[] splited = str.split("\\s");
http://download.oracle.com/javase/tutorial/essential/regex/pre_char_classes.html
Simple to Spit String by Space
String CurrentString = "First Second Last";
String[] separated = CurrentString.split(" ");
for (int i = 0; i < separated.length; i++) {
if (i == 0) {
Log.d("FName ** ", "" + separated[0].trim() + "\n ");
} else if (i == 1) {
Log.d("MName ** ", "" + separated[1].trim() + "\n ");
} else if (i == 2) {
Log.d("LName ** ", "" + separated[2].trim());
}
}
While the accepted answer is good, be aware that you will end up with a leading empty string if your input string starts with a white space. For example, with:
String str = " Hello I'm your String";
String[] splitStr = str.split("\\s+");
The result will be:
splitStr[0] == "";
splitStr[1] == "Hello";
splitStr[2] == "I'm";
splitStr[3] == "Your";
splitStr[4] == "String";
So you might want to trim your string before splitting it:
String str = " Hello I'm your String";
String[] splitStr = str.trim().split("\\s+");
[edit]
In addition to the trim caveat, you might want to consider the unicode non-breaking space character (U+00A0). This character prints just like a regular space in string, and often lurks in copy-pasted text from rich text editors or web pages. They are not handled by .trim() which tests for characters to remove using c <= ' '; \s will not catch them either.
Instead, you can use \p{Blank} but you need to enable unicode character support as well which the regular split won't do. For example, this will work: Pattern.compile("\\p{Blank}", UNICODE_CHARACTER_CLASS).split(words) but it won't do the trim part.
The following demonstrates the problem and provides a solution. It is far from optimal to rely on regex for this, but now that Java has 8bit / 16bit byte representation, an efficient solution for this becomes quite long.
public class SplitStringTest
{
static final Pattern TRIM_UNICODE_PATTERN = Pattern.compile("^\\p{Blank}*(.*)\\p{Blank}$", UNICODE_CHARACTER_CLASS);
static final Pattern SPLIT_SPACE_UNICODE_PATTERN = Pattern.compile("\\p{Blank}", UNICODE_CHARACTER_CLASS);
public static String[] trimSplitUnicodeBySpace(String str)
{
Matcher trimMatcher = TRIM_UNICODE_PATTERN.matcher(str);
boolean ignore = trimMatcher.matches(); // always true but must be called since it does the actual matching/grouping
return SPLIT_SPACE_UNICODE_PATTERN.split(trimMatcher.group(1));
}
@Test
void test()
{
String words = " Hello I'm\u00A0your String\u00A0";
// non-breaking space here --^ and there -----^
String[] split = words.split(" ");
String[] trimAndSplit = words.trim().split(" ");
String[] splitUnicode = SPLIT_SPACE_UNICODE_PATTERN.split(words);
String[] trimAndSplitUnicode = trimSplitUnicodeBySpace(words);
System.out.println("words: [" + words + "]");
System.out.println("split: [" + Arrays.stream(split).collect(Collectors.joining("][")) + "]");
System.out.println("trimAndSplit: [" + Arrays.stream(trimAndSplit).collect(Collectors.joining("][")) + "]");
System.out.println("splitUnicode: [" + Arrays.stream(splitUnicode).collect(Collectors.joining("][")) + "]");
System.out.println("trimAndSplitUnicode: [" + Arrays.stream(trimAndSplitUnicode).collect(Collectors.joining("][")) + "]");
}
}
Results in:
words: [ Hello I'm your String ]
split: [][Hello][I'm your][String ]
trimAndSplit: [Hello][I'm your][String ]
splitUnicode: [][Hello][I'm][your][String]
trimAndSplitUnicode: [Hello][I'm][your][String]
Use Stringutils.split() to split the string by whites paces. For example StringUtils.split("Hello World") returns "Hello" and "World";
In order to solve the mentioned case we use split method like this
String split[]= StringUtils.split("Hello I'm your String");
when we print the split array the output will be :
Hello
I'm
your
String
I do believe that putting a regular expression in the str.split parentheses should solve the issue. The Java String.split() method is based upon regular expressions so what you need is:
str = "Hello I'm your String";
String[] splitStr = str.split("\\s+");
you can saperate string using the below code
String thisString="Hello world";
String[] parts = theString.split(" ");
String first = parts[0];//"hello"
String second = parts[1];//"World"
OK, so we have to do splitting as you already got the answer I would generalize it.
If you want to split any string by spaces, delimiter(special chars).
First, remove the leading space as they create most of the issues.
str1 = " Hello I'm your String ";
str2 = " Are you serious about this question_ boy, aren't you? ";
First remove the leading space which can be space, tab etc.
String s = str1.replaceAll("^\\s+","");//starting with whitespace one or more
Now if you want to split by space or any special char.
String[] sa = s.split("[^\\w]+");//split by any non word char
But as w contains [a-zA-Z_0-9] ,so if you want to split by underscore(_) also use
String[] sa = s.split("[!,? ._'@]+");//for str2 after removing leading space
An alternative way would be:
import java.util.regex.Pattern;
...
private static final Pattern SPACE = Pattern.compile(" ");
String[] arr = SPACE.split(str); // str is the string to be split
Saw it here
if somehow you don't wanna use String split method then you can use StringTokenizer class in Java as..
StringTokenizer tokens = new StringTokenizer("Hello I'm your String", " ");
String[] splited = new String[tokens.countTokens()];
int index = 0;
while(tokens.hasMoreTokens()){
splited[index] = tokens.nextToken();
++index;
}
Since it's been a while since these answers were posted, here's another more current way to do what's asked:
List<String> output = new ArrayList<>();
try (Scanner sc = new Scanner(inputString)) {
while (sc.hasNext()) output.add(sc.next());
}
Now you have a list of strings (which is arguably better than an array); if you do need an array, you can do output.toArray(new String[0]);
Not only white space, but my solution also solves the invisible characters as well.
str = "Hello I'm your String";
String[] splited = str.split("\p{Z}");
Try this one
String str = "This is String";
String[] splited = str.split("\\s+");
String split_one=splited[0];
String split_second=splited[1];
String split_three=splited[2];
Log.d("Splited String ", "Splited String" + split_one+split_second+split_three);
Here is a method to trim a String that has a "," or white space
private String shorterName(String s){
String[] sArr = s.split("\\,|\\s+");
String output = sArr[0];
return output;
}
Very Simple Example below:
Hope it helps.
String str = "Hello I'm your String";
String[] splited = str.split(" ");
var splited = str.split(" ");
var splited1=splited[0]; //Hello
var splited2=splited[1]; //I'm
var splited3=splited[2]; //your
var splited4=splited[3]; //String
Source: Stackoverflow.com