Check if the first character is '\0'. You should also probably check if your pointer is NULL.
char *c = "";
if ((c != NULL) && (c[0] == '\0')) {
printf("c is empty\n");
}
You could put both of those checks in a function to make it convenient and easy to reuse.
Edit: In the if statement can be read like this, "If c is not zero and the first character of character array 'c' is not '\0' or zero, then...".
The && simply combines the two conditions. It is basically like saying this:
if (c != NULL) { /* AND (or &&) */
if (c[0] == '\0') {
printf("c is empty\n");
}
}
You may want to get a good C programming book if that is not clear to you. I could recommend a book called "The C Programming Language".
The shortest version equivalent to the above would be:
if (c && !c[0]) {
printf("c is empty\n");
}
An empty string has one single null byte. So test if (s[0] == (char)0)
Check the pointer for NULL and then using strlen to see if it returns 0.
NULL check is important because passing NULL pointer to strlen invokes an Undefined Behavior.
My preferred method:
if (*ptr == 0) // empty string
Probably more common:
if (strlen(ptr) == 0) // empty string
if (!*ptr) { /* empty string */}
similarly
if (*ptr) { /* not empty */ }
Give it a chance:
Try getting string via function gets(string) then check condition as if(string[0] == '\0')
I would prefer to use the strlen function as library functions are implemented in the best way.
So, I would write if(strlen(p)==0) //Empty string
Source: Stackoverflow.com