[javascript] Regex to Match Symbols: !$%^&*()_+|~-=`{}[]:";'<>?,./

I'm trying to create a Regex test in JavaScript that will test a string to contain any of these characters:

!$%^&*()_+|~-=`{}[]:";'<>?,./

More Info If You're Interested :)

It's for a pretty cool password change application I'm working on. In case you're interested here's the rest of the code.

I have a table that lists password requirements and as end-users types the new password, it will test an array of Regexes and place a checkmark in the corresponding table row if it... checks out :) I just need to add this one in place of the 4th item in the validation array.

var validate = function(password){
    valid = true;

    var validation = [
        RegExp(/[a-z]/).test(password), RegExp(/[A-Z]/).test(password), RegExp(/\d/).test(password), 
        RegExp(/\W|_/).test(password), !RegExp(/\s/).test(password), !RegExp("12345678").test(password), 
        !RegExp($('#txtUsername').val()).test(password), !RegExp("cisco").test(password), 
        !RegExp(/([a-z]|[0-9])\1\1\1/).test(password), (password.length > 7)
    ]

    $.each(validation, function(i){
        if(this)
            $('.form table tr').eq(i+1).attr('class', 'check');
        else{
            $('.form table tr').eq(i+1).attr('class', '');
            valid = false
        }
    });

    return(valid);

}

Yes, there's also corresponding server-side validation!

The most simple and shortest way to accomplish this:

/[^\p{L}\d\s@#]/u

Explanation

[^...] Match a single character not present in the list below

• \p{L} => matches any kind of letter from any language

• \d => matches a digit zero through nine

• \s => matches any kind of invisible character

• @# => @ and # characters

Don't forget to pass the u (unicode) flag.

Answer

/[\W\S_]/

Explanation

This creates a character class removing the word characters, space characters, and adding back the underscore character (as underscore is a "word" character). All that is left is the special characters. Capital letters represent the negation of their lowercase counterparts.

\W will select all non "word" characters equivalent to [^a-zA-Z0-9_]
\S will select all non "whitespace" characters equivalent to [ \t\n\r\f\v]
_ will select "_" because we negate it when using the \W and need to add it back in

Replace all latters from any language in 'A', and if you wish for example all digits to 0:

return str.replace(/[^\s!-@[-`{-~]/g, "A").replace(/\d/g, "0");

// The string must contain at least one special character, escaping reserved RegEx characters to avoid conflict
  const hasSpecial = password => {
    const specialReg = new RegExp(
      '^(?=.*[!@#$%^&*"\\[\\]\\{\\}<>/\\(\\)=\\\\\\-_´+`~\\:;,\\.€\\|])',
    );
    return specialReg.test(password);
  };

A simple way to achieve this is the negative set [^\w\s]. This essentially catches:

• Anything that is not an alphanumeric character (letters and numbers)
• Anything that is not a space, tab, or line break (collectively referred to as whitespace)

For some reason [\W\S] does not work the same way, it doesn't do any filtering. A comment by Zael on one of the answers provides something of an explanation.