For future readers:
This function was abending in Run-time error '13': Type mismatch
Function fnIsNumber(Value) As Boolean
fnIsNumber = Evaluate("ISNUMBER(0+""" & Value & """)")
End Function
In my case, the function was failing when it ran into a #DIV/0!
or N/A
value.
To solve it, I had to do this:
Function fnIsNumber(Value) As Boolean
If CStr(Value) = "Error 2007" Then '<===== This is the important line
fnIsNumber = False
Else
fnIsNumber = Evaluate("ISNUMBER(0+""" & Value & """)")
End If
End Function