Here's a function that does what you want:
import re
def is_match(regex, text):
pattern = re.compile(regex, text)
return pattern.search(text) is not None
The regular expression search method returns an object on success and None if the pattern is not found in the string. With that in mind, we return True as long as the search gives us something back.
Examples:
>>> is_match('ba[rzd]', 'foobar')
True
>>> is_match('ba[zrd]', 'foobaz')
True
>>> is_match('ba[zrd]', 'foobad')
True
>>> is_match('ba[zrd]', 'foobam')
False
Match
objects are always true, and None
is returned if there is no match. Just test for trueness.
Code:
>>> st = 'bar'
>>> m = re.match(r"ba[r|z|d]",st)
>>> if m:
... m.group(0)
...
'bar'
Output = bar
If you want search
functionality
>>> st = "bar"
>>> m = re.search(r"ba[r|z|d]",st)
>>> if m is not None:
... m.group(0)
...
'bar'
and if regexp
not found than
>>> st = "hello"
>>> m = re.search(r"ba[r|z|d]",st)
>>> if m:
... m.group(0)
... else:
... print "no match"
...
no match
As @bukzor mentioned if st = foo bar
than match will not work. So, its more appropriate to use re.search
.
The best one by far is
bool(re.search('ba[rzd]', 'foobarrrr'))
Returns True
You can do something like this:
Using search will return a SRE_match object, if it matches your search string.
>>> import re
>>> m = re.search(u'ba[r|z|d]', 'bar')
>>> m
<_sre.SRE_Match object at 0x02027288>
>>> m.group()
'bar'
>>> n = re.search(u'ba[r|z|d]', 'bas')
>>> n.group()
If not, it will return None
Traceback (most recent call last):
File "<pyshell#17>", line 1, in <module>
n.group()
AttributeError: 'NoneType' object has no attribute 'group'
And just to print it to demonstrate again:
>>> print n
None
Source: Stackoverflow.com