How do I extract the "program name" from a string. The string will look like this :
% O0033(SUB RAD MSD 50R III) G91G1X-6.4Z-2.F500 G3I6.4Z-8. G3I6.4 G3R3.2X6.4F500 G91G0Z5. G91G1X-10.4 G3I10.4 G3R5.2X10.4 G90G0Z2. M99 %
The program name is (SUB RAD MSD 50R III). Storing the result in another string is fine. I'm learning powershell so any explaination of your answers will be appreciated.
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The following regex extract anything between the parenthesis:
PS> $prog = [regex]::match($s,'\(([^\)]+)\)').Groups[1].Value
PS> $prog
SUB RAD MSD 50R III
Explanation (created with RegexBuddy)
Match the character '(' literally «\(»
Match the regular expression below and capture its match into backreference number 1 «([^\)]+)»
Match any character that is NOT a ) character «[^\)]+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character ')' literally «\)»
Check these links:
If program name is always the first thing in (), and doesn't contain other )s than the one at end, then $yourstring -match "[(][^)]+[)]" does the matching, result will be in $Matches[0]
Just to add a non-regex solution:
'(' + $myString.Split('()')[1] + ')'
This splits the string at the parentheses and takes the string from the array with the program name in it.
If you don't need the parentheses, just use:
$myString.Split('()')[1]
Using -replace
$string = '% O0033(SUB RAD MSD 50R III) G91G1X-6.4Z-2.F500 G3I6.4Z-8.G3I6.4 G3R3.2X6.4F500 G91G0Z5. G91G1X-10.4 G3I10.4 G3R5.2X10.4 G90G0Z2. M99 %'
$program = $string -replace '^%\sO\d{4}\((.+?)\).+$','$1'
$program
SUB RAD MSD 50R III
Source: Stackoverflow.com