[ruby] Ruby replace string with captured regex pattern

I am having trouble translating this into Ruby.

Here is a piece of JavaScript that does exactly what I want to do:

function get_code(str){
    return str.replace(/^(Z_.*): .*/,"$1")???????????????????????????;
}

I have tried gsub, sub, and replace but none seem to do what I am expecting.

Here are examples of things I have tried:

"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/) { |capture| capture }
"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "$1")
"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "#{$1}")
"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "\1")
"Z_sdsd: sdsd".gsub(/(.).*/) { |capture| capture }

def get_code(str)
  str.sub(/^(Z_.*): .*/, '\1')
end
get_code('Z_foo: bar!') # => "Z_foo"

 "foobar".gsub(/(o+)/){|s|s+'ball'}
 #=> "fooballbar"

$ variables are only set to matches into the block:

"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/) { "#{ $1.strip }" }

This is also the only way to call a method on the match. This will not change the match, only strip "\1" (leaving it unchanged):

"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "\\1".strip)

If you need to use a regex to filter some results, and THEN use only the capture group, you can do the following:

str = "Leesburg, Virginia  20176"
state_regex = Regexp.new(/,\s*([A-Za-z]{2,})\s*\d{5,}/)
# looks for the comma, possible whitespace, captures alpha,
# looks for possible whitespace, looks for zip

> str[state_regex]
=> ", Virginia  20176"

> str[state_regex, 1] # use the capture group
=> "Virginia"

\1 in double quotes needs to be escaped. So you want either

"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "\\1")

or

"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, '\1')

see the docs on gsub where it says "If it is a double-quoted string, both back-references must be preceded by an additional backslash."

That being said, if you just want the result of the match you can do:

"Z_sdsd: sdsd".scan(/^Z_.*(?=:)/)

or

"Z_sdsd: sdsd"[/^Z_.*(?=:)/]

Note that the (?=:) is a non-capturing group so that the : doesn't show up in your match.