How do I separate an integer into separate digits in an array in JavaScript

Question

This is my code so far   var n   123456789  var d   n toString   length  var digits       var squaredDigits       for  i   d  i  gt   1  i--        var j   k   10      var r    n   k   j  - 0 5      var k   Math pow 10  i       var result   r toFixed         digits push result      console log digits     But when I run my code I get this   9  1  2  3  4  5  6  7  8   If anyone can see the problem or find a better solution I would very much appreciate it

User · Answer

You can get a list of string from your number, by converting it to a string, and then splitting it with an empty string. The result will be an array of strings, each containing a digit:

const num = 124124124
const strArr = `${num}`.split("")

OR to build on this, map each string digit and convert them to a Number:

const intArr = `${num}`.split("").map(x => Number(x))

User · Answer

Update with string interpolation in ES2015   const num   07734  let numStringArr      num   split     map el   gt  parseInt el        0  7  7  3  4

User · Answer

It s very simple  first convert the number to string using the toString   method in JavaScript and then use split   method to convert the string to an array of individual characters   For example  the number is num  then  const numberDigits   num toString   split

User · Answer

Another method here  Since number in Javascript is not splittable by default  you need to convert the number into a string first   var n   123  n toString   split     map Number

User · Answer

It s been a 5  years for this question but heay always welcome to the efficient ways of coding scripting   var n   123456789  var arrayN       n    split     map e   gt  parseInt e

User · Answer

const number   1435  number toString   split     map el  gt parseInt el

User · Answer

x000D   x000D  const toIntArray    n    gt       n       map v   gt   v   x000D   x000D   x000D

User · Answer

I realize this was asked several months ago  but I have an addition to samccone s answer which is more succinct but I don t have the rep to add as a comment   Instead of    123456789  toString 10  split     map function t  return parseInt t      Consider    123456789  toString 10  split     map Number

User · Answer

I ended up solving it as follows    x000D   x000D  const n   123456789  x000D  let toIntArray    n    gt       n       map Number    x000D  console log toIntArray n    x000D   x000D   x000D

User · Answer

Modified the above answer a little bit  We don t really have to call the  map  method explicitly  because it is already built-in into the  Array from  as a second argument  As of MDN      Array from arrayLike   mapFn   thisArg      let num   1234  let arr   Array from String num   Number   console log arr       1  2  3  4

User · Answer

What about   const n   123456  Array from n toString    map Number       1  2  3  4  5  6

User · Answer

Here s an alternative to Nicol  s Fantone s answer  You could argue it s maybe a little less readable  The emphasis is that Array from   can take an optional map function as a parameter  There are some performance gains this way since no intermediate array gets created    const n   123456  Array from n toString     val    gt  Number val        1  2  3  4  5  6

User · Answer

It is pretty short using Array destructuring and String templates    x000D   x000D  const n   12345678  x000D  const digits          n     x000D  console log digits   x000D   x000D   x000D

User · Answer

123456789  toString 10  split          this will return an array of strings   123456789  toString 10  split     map function t  return parseInt t         this will return an array of ints

User · Answer

Why not just do this   var n    123456789  var digits       n  split

User · Answer

x000D   x000D  const toIntArray    n    gt       n       map v   gt   v   x000D   x000D   x000D

User · Answer

This will work for a number greater than 0   You don t need to convert the number into string   function convertNumberToDigitArray number        const arr           while  number  gt  0            let lastDigit   number   10          arr push lastDigit           number   Math floor number   10             return arr

User · Answer

var n   38679  var digits   n toString   split  quot  quot    console log digits    Now the number n is divided to its digits and they are presented in an array  and each element of that array is in string format  To transform them to number format do this  var digitsNum   digits map Number   console log digitsNum    Or get an array with all elements in number format from the beginning  var n   38679  var digits   n toString   split  quot  quot   map Number   console log digits

User · Answer

Suppose  let a   123456  First we will convert it into string and then apply split to convert it into array of characters and then map over it to convert the array to integer  let b   a toString   split     map val  gt parseInt val   console log b

User · Answer

Move   var k   Math pow 10  i     above  var j   k   10

User · Answer

var num   123456789  num   num toString       123456789  var digits   num split           1    2    3    4    5    6    7    8    9

User · Answer

let input   12345664 const output      while  input     0      const roundedInput   Math floor input   10    output push input - roundedInput   10    input   roundedInput   console log output

[javascript] How do I separate an integer into separate digits in an array in JavaScript?

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