This is my code so far:
var n = 123456789;
var d = n.toString().length;
var digits = [];
var squaredDigits = [];
for (i = d; i >= 1; i--) {
var j = k / 10;
var r = (n % k / j) - 0.5;
var k = Math.pow(10, i);
var result = r.toFixed();
digits.push(result);
}
console.log(digits);
But when I run my code I get this: [9, 1, 2, 3, 4, 5, 6, 7, 8]
If anyone can see the problem or find a better solution I would very much appreciate it!
This question is related to
javascript
arrays
digits
var n = 38679;
var digits = n.toString().split("");
console.log(digits);
Now the number n is divided to its digits and they are presented in an array, and each element of that array is in string format. To transform them to number format do this:
var digitsNum = digits.map(Number);
console.log(digitsNum);
Or get an array with all elements in number format from the beginning:
var n = 38679;
var digits = n.toString().split("").map(Number);
console.log(digits);
You can get a list of string from your number, by converting it to a string, and then splitting it with an empty string. The result will be an array of strings, each containing a digit:
const num = 124124124
const strArr = `${num}`.split("")
OR to build on this, map each string digit and convert them to a Number
:
const intArr = `${num}`.split("").map(x => Number(x))
It is pretty short using Array destructuring and String templates:
const n = 12345678;_x000D_
const digits = [...`${n}`];_x000D_
console.log(digits);
_x000D_
let input = 12345664
const output = []
while (input !== 0) {
const roundedInput = Math.floor(input / 10)
output.push(input - roundedInput * 10)
input = roundedInput
}
console.log(output)
Here's an alternative to Nicolás Fantone's answer. You could argue it's maybe a little less readable. The emphasis is that Array.from() can take an optional map function as a parameter. There are some performance gains this way since no intermediate array gets created.
const n = 123456;
Array.from(n.toString(), (val) => Number(val)); // [1, 2, 3, 4, 5, 6]
This will work for a number greater than 0. You don't need to convert the number into string:
function convertNumberToDigitArray(number) {
const arr = [];
while (number > 0) {
let lastDigit = number % 10;
arr.push(lastDigit);
number = Math.floor(number / 10);
}
return arr;
}
const toIntArray = (n) => ([...n + ""].map(v => +v))
_x000D_
It's very simple, first convert the number to string using the toString() method in JavaScript and then use split() method to convert the string to an array of individual characters.
For example, the number is num, then
const numberDigits = num.toString().split('');
Modified the above answer a little bit. We don't really have to call the 'map' method explicitly, because it is already built-in into the 'Array.from' as a second argument. As of MDN.
Array.from(arrayLike[, mapFn[, thisArg]])
let num = 1234;
let arr = Array.from(String(num), Number);
console.log(arr); // [1, 2, 3, 4]
Another method here. Since number in Javascript is not splittable by default, you need to convert the number into a string first.
var n = 123;
n.toString().split('').map(Number);
It's been a 5+ years for this question but heay always welcome to the efficient ways of coding/scripting.
var n = 123456789;
var arrayN = (`${n}`).split("").map(e => parseInt(e))
(123456789).toString(10).split("")
^^ this will return an array of strings
(123456789).toString(10).split("").map(function(t){return parseInt(t)})
^^ this will return an array of ints
const toIntArray = (n) => ([...n + ""].map(v => +v))
_x000D_
const number = 1435;
number.toString().split('').map(el=>parseInt(el));
What about:
const n = 123456;
Array.from(n.toString()).map(Number);
// [1, 2, 3, 4, 5, 6]
Suppose,
let a = 123456
First we will convert it into string and then apply split to convert it into array of characters and then map over it to convert the array to integer.
let b = a.toString().split('').map(val=>parseInt(val))
console.log(b)
Update with string interpolation in ES2015.
const num = 07734;
let numStringArr = `${num}`.split('').map(el => parseInt(el)); // [0, 7, 7, 3, 4]
Move:
var k = Math.pow(10, i);
above
var j = k / 10;
I realize this was asked several months ago, but I have an addition to samccone's answer which is more succinct but I don't have the rep to add as a comment!
Instead of:
(123456789).toString(10).split("").map(function(t){return parseInt(t)})
Consider:
(123456789).toString(10).split("").map(Number)
var num = 123456789;
num = num.toString(); //'123456789'
var digits = num.split(""); //[ '1', '2', '3', '4', '5', '6', '7', '8', '9' ]
I ended up solving it as follows:
const n = 123456789;_x000D_
let toIntArray = (n) => ([...n + ""].map(Number));_x000D_
console.log(toIntArray(n));
_x000D_
Source: Stackoverflow.com