Gets last digit of a number

Question

I need to define the last digit of a number assign this to value   After this  return the last digit   My snippet of code doesn t work correctly     Code   public int lastDigit int number        String temp   Integer toString number       int   guess   new int temp length         int last   guess temp length   - 1        return last      Question      How to solve this issue

User · Answer

public static void main String   args         System out println lastDigit 2347       public static int lastDigit int number          your code goes here       int last   number   10       return last      0 p   7

User · Answer

here is your method  public int lastDigit int number          your code goes here       int last  number 10      return last

User · Answer

Use   int lastDigit   number   10     Read about Modulo operator  http   en wikipedia org wiki Modulo operation  Or  if you want to go with your String solution  String charAtLastPosition   temp charAt temp length  -1

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Just return  number   10   i e  take the modulus  This will be much faster than parsing in and out of a string   If number can be negative then use  Math abs number    10

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Although the best way to do this is to use   if you insist on using strings this will work  public int lastDigit int number    return Integer parseInt String valueOf Integer toString number  charAt Integer toString number  length   - 1         but I just wrote this for completeness  Do not use this code  it is just awful

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Use StringUtils  in case you need string result   String last   StringUtils right number toString    1

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Below is a simpler solution how to get the last digit from an int   public int lastDigit int number    return Math abs number    10

User · Answer

Your array don t have initialization  So it will give default value Zero  You can try like this also  String temp   Integer toString urNumber   System out println temp charAt temp length  -1

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You have just created an empty integer array  The array guess does not contain anything to my knowledge  The rest you should work out to get better

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Another interesting way to do it which would also allow more than just the last number to be taken would be   int number   124454  int overflow    int Math floor number  1 10 n   10 n   int firstDigits   number - overflow    Where n is the number of numbers you wish to conserve lt  code gt    In the above example if n was 1 then the program would return  4  If n was 3 then the program would return 454

User · Answer

No need to use any strings Its over burden   int i   124  int last  i 10  System out println last       prints 4

User · Answer

Without using       public int lastDigit int no       int n1   no   10      n1   no - n1   10      return n1

[java] Gets last digit of a number

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