I'm trying to store the files listing into an array and then loop through the array again.
Below is what I get when I run ls -ls
command from the console.
total 40
36 -rwxrwxr-x 1 amit amit 36720 2012-03-31 12:19 1.txt
4 -rwxrwxr-x 1 amit amit 1318 2012-03-31 14:49 2.txt
The following bash script I've written to store the above data into a bash array.
i=0
ls -ls | while read line
do
array[ $i ]="$line"
(( i++ ))
done
But when I echo $array
, I get nothing!
FYI, I run the script this way: ./bashscript.sh
Here's a variant that lets you use a regex pattern for initial filtering, change the regex to be get the filtering you desire.
files=($(find -E . -type f -regex "^.*$"))
for item in ${files[*]}
do
printf " %s\n" $item
done
This might work for you:
OIFS=$IFS; IFS=$'\n'; array=($(ls -ls)); IFS=$OIFS; echo "${array[1]}"
Running any shell command inside $(...)
will help to store the output in a variable. So using that we can convert the files to array with IFS
.
IFS=' ' read -r -a array <<< $(ls /path/to/dir)
I'd use
files=(*)
And then if you need data about the file, such as size, use the stat
command on each file.
You may be tempted to use (*)
but what if a directory contains the *
character? It's very difficult to handle special characters in filenames correctly.
You can use ls -ls
. However, it fails to handle newline characters.
# Store la -ls as an array
readarray -t files <<< $(ls -ls)
for (( i=1; i<${#files[@]}; i++ ))
{
# Convert current line to an array
line=(${files[$i]})
# Get the filename, joining it together any spaces
fileName=${line[@]:9}
echo $fileName
}
If all you want is the file name, then just use ls
:
for fileName in $(ls); do
echo $fileName
done
See this article or this this post for more information about some of the difficulties of dealing with special characters in file names.
Source: Stackoverflow.com