In the following ip address validation i want to see if it a valid ip address or not how can i do this using the below re
>>> ip="241.1.1.112343434"
>>> aa=re.match(r"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}[^0-9]",ip)
>>> aa.group()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'NoneType' object has no attribute 'group'
try:
parts = ip.split('.')
return len(parts) == 4 and all(0 <= int(part) < 256 for part in parts)
except ValueError:
return False # one of the 'parts' not convertible to integer
except (AttributeError, TypeError):
return False # `ip` isn't even a string
The following will check whether an IP is valid or not: If the IP is within 0.0.0.0 to 255.255.255.255, then the output will be true, otherwise it will be false:
[0<=int(x)<256 for x in re.split('\.',re.match(r'^\d+\.\d+\.\d+\.\d+$',your_ip).group(0))].count(True)==4
Example:
your_ip = "10.10.10.10"
[0<=int(x)<256 for x in re.split('\.',re.match(r'^\d+\.\d+\.\d+\.\d+$',your_ip).group(0))].count(True)==4
Output:
>>> your_ip = "10.10.10.10"
>>> [0<=int(x)<256 for x in re.split('\.',re.match(r'^\d+\.\d+\.\d+\.\d+$',your_ip).group(0))].count(True)==4
True
>>> your_ip = "10.10.10.256"
>>> [0<=int(x)<256 for x in re.split('\.',re.match(r'^\d+\.\d+\.\d+\.\d+$',your_ip).group(0))].count(True)==4
False
>>>
\d{1,3}
will match numbers like 00
or 333
as well which wouldn't be a valid ID.
This is an excellent answer from smink, citing:
ValidIpAddressRegex = "^(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$";
Why not use a library function to validate the ip address?
>>> ip="241.1.1.112343434"
>>> socket.inet_aton(ip)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
socket.error: illegal IP address string passed to inet_aton
Source: Stackoverflow.com