First let's understand what big O, big Theta and big Omega are. They are all sets of functions.
Big O is giving upper asymptotic bound, while big Omega is giving a lower bound. Big Theta gives both.
Everything that is ?(f(n))
is also O(f(n))
, but not the other way around.
T(n)
is said to be in ?(f(n))
if it is both in O(f(n))
and in Omega(f(n))
.
In sets terminology, ?(f(n))
is the intersection of O(f(n))
and Omega(f(n))
For example, merge sort worst case is both O(n*log(n))
and Omega(n*log(n))
- and thus is also ?(n*log(n))
, but it is also O(n^2)
, since n^2
is asymptotically "bigger" than it. However, it is not ?(n^2)
, Since the algorithm is not Omega(n^2)
.
O(n)
is asymptotic upper bound. If T(n)
is O(f(n))
, it means that from a certain n0
, there is a constant C
such that T(n) <= C * f(n)
. On the other hand, big-Omega says there is a constant C2
such that T(n) >= C2 * f(n))
).
Not to be confused with worst, best and average cases analysis: all three (Omega, O, Theta) notation are not related to the best, worst and average cases analysis of algorithms. Each one of these can be applied to each analysis.
We usually use it to analyze complexity of algorithms (like the merge sort example above). When we say "Algorithm A is O(f(n))
", what we really mean is "The algorithms complexity under the worst1 case analysis is O(f(n))
" - meaning - it scales "similar" (or formally, not worse than) the function f(n)
.
Well, there are many reasons for it, but I believe the most important of them are:
To demonstrate this issue, have a look at the following graphs:
It is clear that f(n) = 2*n
is "worse" than f(n) = n
. But the difference is not quite as drastic as it is from the other function. We can see that f(n)=logn
quickly getting much lower than the other functions, and f(n) = n^2
is quickly getting much higher than the others.
So - because of the reasons above, we "ignore" the constant factors (2* in the graphs example), and take only the big-O notation.
In the above example, f(n)=n, f(n)=2*n
will both be in O(n)
and in Omega(n)
- and thus will also be in Theta(n)
.
On the other hand - f(n)=logn
will be in O(n)
(it is "better" than f(n)=n
), but will NOT be in Omega(n)
- and thus will also NOT be in Theta(n)
.
Symetrically, f(n)=n^2
will be in Omega(n)
, but NOT in O(n)
, and thus - is also NOT Theta(n)
.
1Usually, though not always. when the analysis class (worst, average and best) is missing, we really mean the worst case.