I am having something like:
<table id="tblOne">
<tbody>
<tr>
<td>
<table id="tblTwo">
<tbody>
<tr>
<td>
Items
</td>
</tr>
<tr>
<td>
Prod
</td>
</tr>
</tbody>
</table>
</td>
</tr>
<tr>
<td>
Item 1
</td>
</tr>
<tr>
<td>
Item 2
</td>
</tr>
</tbody>
</table>
I have written jQuery to loop through each tr like:
$('#tblOne tr').each(function() {...code...});
But problem is that it loops through the "tr" of "tblTwo" also which I don't want. Can anyone please suggest something to solve this?
This question is related to
javascript
jquery
html-table
each
tablerow
In jQuery just use:
$('#tblOne > tbody > tr').each(function() {...code...});
Using the children selector (>) you will walk over all the children (and not all descendents), example with three rows:
$('table > tbody > tr').each(function(index, tr) {
console.log(index);
console.log(tr);
});
Result:
0
<tr>
1
<tr>
2
<tr>
In VanillaJS you can use document.querySelectorAll() and walk over the rows using forEach()
[].forEach.call(document.querySelectorAll('#tblOne > tbody > tr'), function(index, tr) {
/* console.log(index); */
/* console.log(tr); */
});
Use immediate children selector >:
$('#tblOne > tbody > tr')
Description: Selects all direct child elements specified by "child" of elements specified by "parent".
Just a recommendation:
I'd recommend using the DOM table implementation, it's very straight forward and easy to use, you really don't need jQuery for this task.
var table = document.getElementById('tblOne');
var rowLength = table.rows.length;
for(var i=0; i<rowLength; i+=1){
var row = table.rows[i];
//your code goes here, looping over every row.
//cells are accessed as easy
var cellLength = row.cells.length;
for(var y=0; y<cellLength; y+=1){
var cell = row.cells[y];
//do something with every cell here
}
}
Source: Stackoverflow.com