I am having a little trouble with namespaces and the use statements.
I have three files: ShapeInterface.php, Shape.php and Circle.php.
I am trying to do this using relative paths so I have put this in all of the classes:
namespace Shape;
In my circle class I have the following:
namespace Shape;
//use Shape;
//use ShapeInterface;
include 'Shape.php';
include 'ShapeInterface.php';
class Circle extends Shape implements ShapeInterface{ ....
If I use the include statements I get no errors. If I try the use statements I get:
Fatal error: Class 'Shape\Shape' not found in /Users/shawn/Documents/work/sites/workspace/shape/Circle.php on line 8
Could someone please give me a little guidance on the issue?
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php
namespaces
The use operator is for giving aliases to names of classes, interfaces or other namespaces. Most use statements refer to a namespace or class that you'd like to shorten:
use My\Full\Namespace;
is equivalent to:
use My\Full\Namespace as Namespace;
// Namespace\Foo is now shorthand for My\Full\Namespace\Foo
If the use operator is used with a class or interface name, it has the following uses:
// after this, "new DifferentName();" would instantiate a My\Full\Classname
use My\Full\Classname as DifferentName;
// global class - making "new ArrayObject()" and "new \ArrayObject()" equivalent
use ArrayObject;
The use operator is not to be confused with autoloading. A class is autoloaded (negating the need for include) by registering an autoloader (e.g. with spl_autoload_register). You might want to read PSR-4 to see a suitable autoloader implementation.
If you need to order your code into namespaces, just use the keyword namespace:
file1.php
namespace foo\bar;
In file2.php
$obj = new \foo\bar\myObj();
You can also use use. If in file2 you put
use foo\bar as mypath;
you need to use mypath instead of bar anywhere in the file:
$obj = new mypath\myObj();
Using use foo\bar; is equal to use foo\bar as bar;.
Source: Stackoverflow.com