I have a common command that gets called from within very specific directories. There is only one executable sitting in /bin for this program, and the current working directory is very important for running it correctly. The script affects the files that live inside the directory it is run within.
Now, I also have a custom shell script that does some things in one directory, but I need to call that command mentioned above as if it was in another directory.
How do you do this in a shell script?
This question is related to
bash
shell
working-directory
You can use the cd builtin, or the pushd and popd builtins for this purpose. For example:
# do something with /etc as the working directory
cd /etc
:
# do something with /tmp as the working directory
cd /tmp
:
You use the builtins just like any other command, and can change directory context as many times as you like in a script.
current_dir=$PWD;cd /path/to/your/command/dir;special command ARGS;cd $current_dir;
current_dir equal to your pwd cd to where you need to run your commandcd back to our variable current_dirAnother Solution by @apieceofbart
pushd && YOUR COMMAND && popd
Use cd in a subshell; the shorthand way to use this kind of subshell is parentheses.
(cd wherever; mycommand ...)
That said, if your command has an environment that it requires, it should really ensure that environment itself instead of putting the onus on anything that might want to use it (unless it's an internal command used in very specific circumstances in the context of a well defined larger system, such that any caller already needs to ensure the environment it requires). Usually this would be some kind of shell script wrapper.
(cd /path/to/your/special/place;/bin/your-special-command ARGS)
Source: Stackoverflow.com