How to convert a time string to seconds

Question

I need to convert time value strings given in the following format to seconds  for example   1  00 00 00 000  - gt  0 seconds  2  00 00 10 000  - gt  10 seconds  3  00 01 04 000  - gt  64 seconds  4  01 01 09 000  - gt  3669 seconds   Do I need to use regex to do this  I tried to use the time module  but   time strptime  00 00 00 000    I  M  S     throws    ValueError  time data  00 00 00 000  does not match format   I  M  S      Edit   Looks like this   from datetime import datetime pt   datetime strptime timestring   H  M  S  f   total seconds   pt second   pt minute 60   pt hour 3600   gives the correct result  I was just using the wrong module

User · Answer

Inspired by sverrir-sigmundarson s comment   def time to sec time str       return sum x   int t  for x  t in zip  1  60  3600   reversed time str split

User · Answer

def time to sec time       sep           rest   time split sep  1  0      splitted   rest split  quot   quot       emel   len splitted  - 1     i   0     summa   0     for numb in splitted          szor   60     emel - i          i    1         summa    int numb    szor     return summa

User · Answer

without imports  time    01 34 11  sum x   int t  for x  t in zip  3600  60  1   time split

User · Answer

There is always parsing by hand   gt  gt  gt  import re  gt  gt  gt  ts     00 00 00 000    00 00 10 000    00 01 04 000    01 01 09 000    gt  gt  gt  for t in ts          times   map int  re split r        t           print t  times 0  3600 times 1  60 times 2  times 3  1000       00 00 00 000 0 0 00 00 10 000 10 0 00 01 04 000 64 0 01 01 09 000 3669 0  gt  gt  gt

User · Answer

def time to sec t      h  m  s   map int  t split          return h   3600   m   60   s  t    10 40 20  time to sec t     38420

User · Answer

For Python 2 7    gt  gt  gt  import datetime  gt  gt  gt  import time  gt  gt  gt  x   time strptime  00 01 00 000  split      0    H  M  S    gt  gt  gt  datetime timedelta hours x tm hour minutes x tm min seconds x tm sec  total seconds   60 0

User · Answer

A little more pythonic way I think would be   timestr    00 04 23   ftr    3600 60 1   sum  a b for a b in zip ftr  map int timestr split            Output is 263Sec   I would be interested to see if anyone could simplify it further

User · Answer

It looks like you re willing to strip fractions of a second    the problem is you can t use  00  as the hour with  I   gt  gt  gt  time strptime  00 00 00 000  split      0    H  M  S   time struct time tm year 1900  tm mon 1  tm mday 1  tm hour 0  tm min 0  tm sec 0  tm wday 0  tm yday 1  tm isdst -1   gt  gt  gt

User · Answer

import time from datetime import datetime  t1   datetime now   replace microsecond 0  time sleep 3  now   datetime now   replace microsecond 0  print  now - t1  total seconds      result      3 0

User · Answer

To get the timedelta    you should subtract 1900-01-01    gt  gt  gt  from datetime import datetime  gt  gt  gt  datetime strptime  01 01 09 000     H  M  S  f   datetime datetime 1900  1  1  1  1  9   gt  gt  gt  td   datetime strptime  01 01 09 000     H  M  S  f   - datetime 1900 1 1   gt  gt  gt  td datetime timedelta 0  3669   gt  gt  gt  td total seconds     2 7  3669 0    H above implies the input is less than a day  to support the time difference more than a day    gt  gt  gt  import re  gt  gt  gt  from datetime import timedelta  gt  gt  gt  td   timedelta   dict zip  hours minutes seconds milliseconds  split                                  map int  re findall   d     31 01 09 000        gt  gt  gt  td datetime timedelta 1  25269   gt  gt  gt  td total seconds   111669 0   To emulate  total seconds   on Python 2 6    gt  gt  gt  from   future   import division  gt  gt  gt    td days   86400   td seconds    10  6   td microseconds    10  6 111669 0

[python] How to convert a time string to seconds?

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