Possible Duplicate:
Looping through the content of a file in Bash?
I have one file with a list of names. I need to loop through all names in this file from an external file with a shell script. How can I do that?
Example files:
scripts/names.txt
alison
barb
charlie
david
scripts/script.sh
NAMES="" #names from names.txt file
for NAME in $NAMES; do
echo "$NAME"
done
How can I explode the names.txt file into an array in a separate shell script?
This might work for you:
cat <<\! >names.txt
> alison
> barb
> charlie
> david
> !
OIFS=$IFS; IFS=$'\n'; NAMES=($(<names.txt)); IFS=$OIFS
echo "${NAMES[@]}"
alison barb charlie david
echo "${NAMES[0]}"
alison
for NAME in "${NAMES[@]}";do echo $NAME;done
alison
barb
charlie
david
cat names.txt|while read line; do
echo "$line";
done
I know the purists will hate this method, but you can cat
the file.
NAMES=`cat scripts/names.txt` #names from names.txt file
for NAME in $NAMES; do
echo "$NAME"
done
You'll be wanting to use the 'read' command
while read name
do
echo "$name"
done < names.txt
Note that "$name" is quoted -- if it's not, it will be split using the characters in $IFS
as delimiters. This probably won't be noticed if you're just echoing the variable, but if your file contains a list of file names which you want to copy, those will get broken down by $IFS
if the variable is unquoted, which is not what you want or expect.
If you want to use Mike Clark's approach (loading into a variable rather than using read), you can do it without the use of cat
:
NAMES="$(< scripts/names.txt)" #names from names.txt file
for NAME in $NAMES; do
echo "$NAME"
done
The problem with this is that it loads the whole file into $NAMES
, when you read it back out, you can either get the whole file (if quoted) or the file broken down by $IFS
, if not quoted. By default, this will give you individual words, not individual lines. So if the name "Mary Jane" appeared on a line, you would get "Mary" and "Jane" as two separate names. Using read
will get around this... although you could also change the value of $IFS
Source: Stackoverflow.com