[python] How to change values in a tuple?

tldr; the "workaround" is creating a new tuple object, not actually modifying the original

While this is a very old question, someone told me about this Python mutating tuples madness. Which I was very much surprised/intrigued, and doing some googling, I landed here (and other similar samples online)

I ran some test to prove my theory

Note == does value equality while is does referential equality (is obj a the same instance as obj b)

a = ("apple", "canana", "cherry")
b = tuple(["apple", "canana", "cherry"])
c = a

print("a: " + str(a))
print("b: " + str(b))
print("c: " + str(c))
print("a == b :: %s" % (a==b))
print("b == c :: %s" % (b==c))
print("a == c :: %s" % (a==c))
print("a is b :: %s" % (a is b))
print("b is c :: %s" % (b is c))
print("a is c :: %s" % (a is c))

d = list(a)
d[1] = "kiwi"
a = tuple(d)

print("a: " + str(a))
print("b: " + str(b))
print("c: " + str(c))
print("a == b :: %s" % (a==b))
print("b == c :: %s" % (b==c))
print("a == c :: %s" % (a==c))
print("a is b :: %s" % (a is b))
print("b is c :: %s" % (b is c))
print("a is c :: %s" % (a is c))

Yields:

a: ('apple', 'canana', 'cherry')
b: ('apple', 'canana', 'cherry')
c: ('apple', 'canana', 'cherry')
a == b :: True
b == c :: True
a == c :: True
a is b :: False
b is c :: False
a is c :: True
a: ('apple', 'kiwi', 'cherry')
b: ('apple', 'canana', 'cherry')
c: ('apple', 'canana', 'cherry')
a == b :: False
b == c :: True
a == c :: False
a is b :: False
b is c :: False
a is c :: False