Python open gives FileNotFoundError IOError Errno 2 No such file or directory

Question

For some reason my code is having trouble opening a simple file  This is the code  file1   open  recentlyUpdated yaml    And the error is  IOError   Errno 2  No such file or directory   recentlyUpdated yaml    Naturally I checked that this is the correct name of the file  I have tried moving around the file  giving open   the full path to the file and none of it seems to work

User · Answer

The file may be existing but may have a different path. Try writing the absolute path for the file.

Try os.listdir() function to check that atleast python sees the file.

Try it like this:

file1 = open(r'Drive:\Dir\recentlyUpdated.yaml')

User · Answer

Most likely  the problem is that you re using a relative file path to open the file  but the current working directory isn t set to what you think it is   It s a common misconception that relative paths are relative to the location of the python script  but this is untrue  Relative file paths are always relative to the current working directory  and the current working directory doesn t have to be the location of your python script   You have three options    Use an absolute path to open the file   file   open r C  path to your file yaml    Generate the path to the file relative to your python script   from pathlib import Path  script location   Path   file    absolute   parent file location   script location    file yaml  file   file location open      See also  How do I get the path and name of the file that is currently executing   Change the current working directory before opening the file   import os  os chdir r C  path to your file   file   open  file yaml        Other common mistakes that could cause a  file not found  error include    Accidentally using escape sequences in a file path   path    C  Users newton file yaml    Incorrect  The   n  in  Users newton  is a line break character    To avoid making this mistake  remember to use raw string literals for file paths   path   r C  Users newton file yaml    Correct     See also  Windows path in Python  Forgetting that Windows doesn t display file extensions   Since Windows doesn t display known file extensions  sometimes when you think your file is named file yaml  it s actually named file yaml yaml  Double-check your file s extension

User · Answer

Possibly  you closed the  file1   Just use  w  flag  that create new file   file1   open  recentlyUpdated yaml    w        mode is an optional string that specifies the mode in which the file   is opened  It defaults to  r  which means open for reading in text   mode  Other common values are  w  for writing  truncating the file if   it already exists        see also https   docs python org 3 library functions html highlight open open

User · Answer

If is VSCode see the workspace  If you are in other workspace this error can rise

User · Answer

Make sure the file exists  use os listdir   to see the list of files in the current working directory Make sure you re in the directory you think you re in with os getcwd    if you launch your code from an IDE  you may well be in a different directory  You can then either    Call os chdir dir   dir being the folder where the file is located  then open the file with just its name like you were doing  Specify an absolute path to the file in your open call   Remember to use a raw string if your path uses backslashes  like so  dir   r C  Python32    If you don t use raw-string  you have to escape every backslash   C   User  Bob       Forward-slashes also work on Windows  C  Python32  and do not need to be escaped     Let me clarify how Python finds files     An absolute path is a path that starts with your computer s root directory  for example  C  Python scripts    if you re on Windows   A relative path is a path that does not start with your computer s root directory  and is instead relative to something called the working directory  You can view Python s current working directory by calling os getcwd       If you try to do open  sortedLists yaml    Python will see that you are passing it a relative path  so it will search for the file inside the current working directory  Calling os chdir will change the current working directory   Example  Let s say file txt is found in C  Folder   To open it  you can do   os chdir r C  Folder   open  file txt    relative path  looks inside the current working directory   or   open r C  Folder file txt    full path

[python] Python open() gives FileNotFoundError/IOError: Errno 2 No such file or directory

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