I need to add elements to an ArrayList queue whatever, but when I call the function to add an element, I want it to add the element at the beginning of the array (so it has the lowest index) and if the array has 10 elements adding a new results in deleting the oldest element (the one with the highest index).
Does anyone have any suggestions?
import java.util.*:
public class Logic {
List<String> list = new ArrayList<String>();
public static void main(String...args) {
Scanner input = new Scanner(System.in);
Logic obj = new Logic();
for (int i=0;i<=20;i++) {
String string = input.nextLine();
obj.myLogic(string);
obj.printList();
}
}
public void myLogic(String strObj) {
if (this.list.size()>=10) {
this.list.remove(this.list.size()-1);
} else {
list.add(strObj);
}
}
public void printList() {
System.out.print(this.list);
}
}
You can use list methods, remove and add
list.add(lowestIndex, element);
list.remove(highestIndex, element);
Java LinkedList provides both the addFirst(E e) and the push(E e) method that add an element to the front of the list.
https://docs.oracle.com/javase/7/docs/api/java/util/LinkedList.html#addFirst(E)
You can take a look at the add(int index, E element):
Inserts the specified element at the specified position in this list. Shifts the element currently at that position (if any) and any subsequent elements to the right (adds one to their indices).
Once you add you can then check the size of the ArrayList and remove the ones at the end.
import com.google.common.collect.Lists;
import java.util.List;
/**
* @author Ciccotta Andrea on 06/11/2020.
*/
public class CollectionUtils {
/**
* It models the prepend O(1), used against the common append/add O(n)
* @param head first element of the list
* @param body rest of the elements of the list
* @return new list (with different memory-reference) made by [head, ...body]
*/
public static <E> List<Object> prepend(final E head, List<E> final body){
return Lists.asList(head, body.toArray());
}
/**
* it models the typed version of prepend(E head, List<E> body)
* @param type the array into which the elements of this list are to be stored
*/
public static <E> List<E> prepend(final E head, List<E> body, final E[] type){
return Lists.asList(head, body.toArray(type));
}
}
I think the implement should be easy, but considering about the efficiency, you should use LinkedList but not ArrayList as the container. You can refer to the following code:
import java.util.LinkedList;
import java.util.List;
public class DataContainer {
private List<Integer> list;
int length = 10;
public void addDataToArrayList(int data){
list.add(0, data);
if(list.size()>10){
list.remove(length);
}
}
public static void main(String[] args) {
DataContainer comp = new DataContainer();
comp.list = new LinkedList<Integer>();
int cycleCount = 100000000;
for(int i = 0; i < cycleCount; i ++){
comp.addDataToArrayList(i);
}
}
}
Take this example :-
List<String> element1 = new ArrayList<>();
element1.add("two");
element1.add("three");
List<String> element2 = new ArrayList<>();
element2.add("one");
element2.addAll(element1);
You can use
public List<E> addToListStart(List<E> list, E obj){
list.add(0,obj);
return (List<E>)list;
}
Change E with your datatype
If deleting the oldest element is necessary then you can add:
list.remove(list.size()-1);
before return statement. Otherwise list will add your object at beginning and also retain oldest element.
This will delete last element in list.
There are various data structures which are optimized for adding elements at the first index. Mind though, that if you convert your collection to one of these, the conversation will probably need a time and space complexity of O(n)
The JDK includes the Deque structure which offers methods like addFirst(e) and offerFirst(e)
Deque<String> deque = new LinkedList<>();
deque.add("two");
deque.add("one");
deque.addFirst("three");
//prints "three", "two", "one"
Space and time complexity of insertion is with LinkedList constant (O(1)). See the Big-O cheatsheet.
A very easy but inefficient method is to use reverse:
Collections.reverse(list);
list.add(elementForTop);
Collections.reverse(list);
If you use Java 8 streams, this answer might interest you.
O(n)O(1)Looking at the JDK implementation this has a O(n) time complexity so only suitable for very small lists.
I had a similar problem, trying to add an element at the beginning of an existing array, shift the existing elements to the right and discard the oldest one (array[length-1]). My solution might not be very performant but it works for my purposes.
Method:
updateArray (Element to insert)
- for all the elements of the Array
- start from the end and replace with the one on the left;
- Array [0] <- Element
Good luck
You may want to look at Deque. it gives you direct access to both the first and last items in the list.
What you are describing, is an appropriate situation to use Queue.
Since you want to add new element, and remove the old one. You can add at the end, and remove from the beginning. That will not make much of a difference.
Queue has methods add(e) and remove() which adds at the end the new element, and removes from the beginning the old element, respectively.
Queue<Integer> queue = new LinkedList<Integer>();
queue.add(5);
queue.add(6);
queue.remove(); // Remove 5
So, every time you add an element to the queue you can back it up with a remove method call.
UPDATE: -
And if you want to fix the size of the Queue, then you can take a look at: - ApacheCommons#CircularFifoBuffer
From the documentation: -
CircularFifoBuffer is a first in first out buffer with a fixed size that replaces its oldest element if full.
Buffer queue = new CircularFifoBuffer(2); // Max size
queue.add(5);
queue.add(6);
queue.add(7); // Automatically removes the first element `5`
As you can see, when the maximum size is reached, then adding new element automatically removes the first element inserted.
you can use this code
private List myList = new ArrayList();
private void addItemToList(Object obj){
if(myList.size()<10){
myList.add(0,obj);
}else{
myList.add(0,obj);
myList.remove(10);
}
}
Source: Stackoverflow.com