[sql] How to use SQL LIKE condition with multiple values in PostgreSQL?

Is there any shorter way to look for multiple matches:

 SELECT * 
 from table 
 WHERE column LIKE "AAA%" 
    OR column LIKE "BBB%" 
    OR column LIKE "CCC%"

This questions applies to PostgreSQL 9.1, but if there is a generic solution it would be even better.

Using array or set comparisons:

create table t (str text);
insert into t values ('AAA'), ('BBB'), ('DDD999YYY'), ('DDD099YYY');

select str from t
where str like any ('{"AAA%", "BBB%", "CCC%"}');

select str from t
where str like any (values('AAA%'), ('BBB%'), ('CCC%'));

It is also possible to do an AND which would not be easy with a regex if it were to match any order:

select str from t
where str like all ('{"%999%", "DDD%"}');

select str from t
where str like all (values('%999%'), ('DDD%'));

You might be able to use IN, if you don't actually need wildcards.

SELECT * from table WHERE column IN ('AAA', 'BBB', 'CCC')

You can use regular expression operator (~), separated by (|) as described in Pattern Matching

select column_a from table where column_a ~* 'aaa|bbb|ccc'

Use LIKE ANY(ARRAY['AAA%', 'BBB%', 'CCC%']) as per this cool trick @maniek showed earlier today.

Following query helped me. Instead of using LIKE, you can use ~*.

select id, name from hosts where name ~* 'julia|lena|jack';