You can use numpy.logical_not
to invert the boolean array returned by isin
:
In [63]: s = pd.Series(np.arange(10.0))
In [64]: x = range(4, 8)
In [65]: mask = np.logical_not(s.isin(x))
In [66]: s[mask]
Out[66]:
0 0
1 1
2 2
3 3
8 8
9 9
As given in the comment by Wes McKinney you can also use
s[~s.isin(x)]