I'd like to know what switch you pass to the gcc compiler to turn off unused variable warnings? I'm getting errors out of boost on windows and I do not want to touch the boost code:
C:\boost_1_52_0/boost/system/error_code.hpp: At global scope:
C:\boost_1_52_0/boost/system/error_code.hpp:214:36: error: 'boost::system::posix_category' defined but not used [-Werror=unused-variable]
C:\boost_1_52_0/boost/system/error_code.hpp:215:36: error: 'boost::system::errno_ecat' defined but not used [-Werror=unused-variable]
C:\boost_1_52_0/boost/system/error_code.hpp:216:36: error: 'boost::system::native_ecat' defined but not used [-Werror=unused-variable]
I tried using both -Wunused-value
and -Wno-unused-value
but neither suppressed the messages above.
What is the right command, here is my compile line:
g++ -g -fno-inline -Wall -Werror -Wextra -Wfloat-equal -Wshadow
-Wpointer-arith -Wcast-qual -Wcast-align -Wwrite-strings -Wno-conversion
-Wdisabled-optimization -Wredundant-decls -Wunused-value -Wno-deprecated
-IC:\\boost_1_52_0 -D_LARGEFILE_SOURCE -D_LARGEFILE64_SOURCE -D_FILE_OFFSET_BITS=64
-c -o op.o op.cpp
Perhaps the -Wall
overrides my goal?
This question is related to
c++
gcc
compiler-warnings
compiler-flags
-Wall
and -Wextra
sets the stage in GCC and the subsequent -Wno-unused-variable
may not take effect. For example, if you have:
CFLAGS += -std=c99 -pedantic -pedantic-errors -Werror -g0 -Os \
-fno-strict-overflow -fno-strict-aliasing \
-Wall -Wextra \
-pthread \
-Wno-unused-label \
-Wno-unused-function \
-Wno-unused-parameter \
-Wno-unused-variable \
$(INC)
then GCC sees the instruction -Wall -Wextra
and seems to ignore -Wno-unused-variable
This can instead look like this below and you get the desired effect of not being stopped in your compile on the unused variable:
CFLAGS += -std=c99 -pedantic -pedantic-errors -Werror -g0 -Os \
-fno-strict-overflow -fno-strict-aliasing \
-pthread \
-Wno-unused-label \
-Wno-unused-function \
$(INC)
There is a good reason it is called a "warning" vs an "error". Failing the compile just because you code is not complete (say you are stubbing the algorithm out) can be defeating.
How do you disable the unused variable warnings coming out of gcc?
I'm getting errors out of boost on windows and I do not want to touch the boost code...
You visit Boost's Trac and file a bug report against Boost.
Your application is not responsible for clearing library warnings and errors. The library is responsible for clearing its own warnings and errors.
Use -Wno-unused-variable
should work.
export IGNORE_WARNINGS=1
It does display warnings, but continues with the build
If you're using gcc and want to disable the warning for selected code, you can use the #pragma compiler directive:
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wunused-variable"
( your problematic library includes )
#pragma GCC diagnostic pop
For code you control, you may also use __attribute__((unused))
to instruct the compiler that specific variables are not used.
See man gcc
under Warning Options. There you have a whole bunch of unused
Warning Options
... -Wunused -Wunused-function -Wunused-label -Wunused-parameter -Wunused-value -Wunused-variable -Wunused-but-set-parameter -Wunused-but-set-variable
If you prefix any of them with no-
, it will disable this warning.
Many options have long names starting with -f or with -W---for example, -fmove-loop-invariants, -Wformat and so on. Most of these have both positive and negative forms; the negative form of -ffoo would be -fno-foo. This manual documents only one of these two forms, whichever one is not the default.
More detailed explanation can be found at Options to Request or Suppress Warnings
The compiler is already telling you, it's not value
but variable
. You are looking for -Wno-unused-variable
. Also, try g++ --help=warnings
to see a list of available options.
Sometimes you just need to suppress only some warnings and you want to keep other warnings, just to be safe. In your code, you can suppress the warnings for variables and even formal parameters by using GCC's unused attribute. Lets say you have this code snippet:
void func(unsigned number, const int version)
{
unsigned tmp;
std::cout << number << std::endl;
}
There might be a situation, when you need to use this function as a handler - which (imho) is quite common in C++ Boost library. Then you need the second formal parameter version, so the function's signature is the same as the template the handler requires, otherwise the compilation would fail. But you don't really need it in the function itself either...
The solution how to mark variable or the formal parameter to be excluded from warnings is this:
void func(unsigned number, const int version __attribute__((unused)))
{
unsigned tmp __attribute__((unused));
std::cout << number << std::endl;
}
GCC has many other parameters, you can check them in the man pages. This also works for the C programs, not only C++, and I think it can be used in almost every function, not just handlers. Go ahead and try it! ;)
P.S.: Lately I used this to suppress warnings of Boosts' serialization in template like this:
template <typename Archive>
void serialize(Archive &ar, const unsigned int version __attribute__((unused)))
EDIT: Apparently, I didn't answer your question as you needed, drak0sha done it better. It's because I mainly followed the title of the question, my bad. Hopefully, this might help other people, who get here because of that title... :)
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