I have array in subdocument like this
{
"_id" : ObjectId("512e28984815cbfcb21646a7"),
"list" : [
{
"a" : 1
},
{
"a" : 2
},
{
"a" : 3
},
{
"a" : 4
},
{
"a" : 5
}
]
}
Can I filter subdocument for a > 3
My expect result below
{
"_id" : ObjectId("512e28984815cbfcb21646a7"),
"list" : [
{
"a" : 4
},
{
"a" : 5
}
]
}
I try to use $elemMatch
but returns the first matching element in the array
My query:
db.test.find( { _id" : ObjectId("512e28984815cbfcb21646a7") }, {
list: {
$elemMatch:
{ a: { $gt:3 }
}
}
} )
The result return one element in array
{ "_id" : ObjectId("512e28984815cbfcb21646a7"), "list" : [ { "a" : 4 } ] }
and I try to use aggregate with $match
but not work
db.test.aggregate({$match:{_id:ObjectId("512e28984815cbfcb21646a7"), 'list.a':{$gte:5} }})
It's return all element in array
{
"_id" : ObjectId("512e28984815cbfcb21646a7"),
"list" : [
{
"a" : 1
},
{
"a" : 2
},
{
"a" : 3
},
{
"a" : 4
},
{
"a" : 5
}
]
}
Can I filter element in array to get result as expect result?
This question is related to
mongodb
filter
mongodb-query
aggregation-framework
Selects a subset of the array to return based on the specified condition. Returns an array with only those elements that match the condition. The returned elements are in the original order.
db.test.aggregate([
{$match: {"list.a": {$gt:3}}}, // <-- match only the document which have a matching element
{$project: {
list: {$filter: {
input: "$list",
as: "list",
cond: {$gt: ["$$list.a", 3]} //<-- filter sub-array based on condition
}}
}}
]);
Above solution works best if multiple matching sub documents are required. $elemMatch also comes in very use if single matching sub document is required as output
db.test.find({list: {$elemMatch: {a: 1}}}, {'list.$': 1})
Result:
{
"_id": ObjectId("..."),
"list": [{a: 1}]
}
Source: Stackoverflow.com