regular expression to validate datetime format MM DD YYYY

Question

I am trying to validate datetime format MM DD YYYY  Here is the code I am trying please help    function ValidateDate testdate            var Status         var reg        0 1-9   12  d 3 01     0 13578  1 02      19  2-9  d  d 2      0 1-9   12  d 30    0 13456789  1 012      19  2-9  d  d 2      0 1-9  1 d 2 0-8    02    19  2-9  d  d 2     29  02    1 6-9   2-9  d  0 48   2468  048   13579  26     16  2468  048   3579  26  00      g          if   reg test testdate                 Status   false                    return Status

User · Answer

based on this

dd-mm-yy

I modified the original to this:

^(?:(?:(?:0?[13578]|1[02]|(?:Jan|Mar|May|Jul|Aug|Oct|Dec))(\/|-|\.)31)\1|(?:(?:0?[1,3-9]|1[0-2]|(?:Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))(\/|-|\.)(?:29|30)\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:(?:0?2|(?:Feb))(\/|-|\.)(?:29)\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:(?:0?[1-9]|(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep))|(?:1[0-2]|(?:Oct|Nov|Dec)))(\/|-|\.)(?:0?[1-9]|1\d|2[0-8])\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$

test the regex here

User · Answer

you can look into this link and I hope this may be of great help as its was for me   If you are using the regex given in the above link in Java code then use the following regex     0 1-9  1 012   -     0 1-9   12  0-9  3 01   -     19 20   d  d    As I noticed in your example you are using js function then this use regex      0 1-9  1 012   -     0 1-9   12  0-9  3 01   -     19 20  d d    This will match a date in mm dd yyyy format from between 1900-01-01 and 2099-12-31  with a choice of four separators   and not to forget the   return regex test testdate

User · Answer

In this case  to validate Date  DD-MM-YYYY  or  DD MM YYYY   with a year between 1900 and 2099 like this with month and Days validation   if   Regex Match txtDob Text      0 1-9  1 0-9  2 0-9  3 0 1      -   0 1-9  1 0-2      -   19 20  0-9  2     Success                         MessageBox Show  InValid Date of Birth       txtDob Focus

User · Answer

It s long  but great   new RegExp      d           10 D   0  5-9  1 0-4   D   1582      0 9 D   0  3-9  1 0-3   D   1752       0  13578  1 02      0  469  11      31    -31      31     0 2           29    000 04        1  0-6   2468   048   3579   26  00            d d     02468  048   13579  26      x20BC      00   42 3 0369  2 147  1 258  09  x20BC          0 2           d D      01  d     2 0-8        -      0  1-9   12  d 3 01   2   0000        00   4 0-5   0-3   d  x20BC      d 4     x20BC    d 4     x20BC            x20 d  x20          0  1-9  1 012       0-5  d  0 2     x20 aApP  mM        01  d 2 0-3       0-5  d  1 2

User · Answer

The answer marked is perfect but for one scenario  where in the dd and mm are actually single digits  the following regex is perfect in this case    x000D   x000D      function validateDate testdate    x000D          var date regex      0  1-9  1 0-2     0  1-9  1 d 2 d 3 01     19 20  d 2      x000D          return date regex test testdate   x000D        x000D   x000D   x000D

User · Answer

Try your regex with a tool like http   jsregex com   There is many  or better  a unit test   For a naive validation    function validateDate testdate        var date regex      d 2    d 2    d 4          return date regex test testdate       In your case  to validate  MM DD YYYY   with a year between 1900 and 2099  I ll write it like that    function validateDate testdate        var date regex      0 1-9  1 0-2     0 1-9  1 d 2 d 3 01     19 20  d 2          return date regex test testdate

User · Answer

var pattern   new RegExp  0 1  0-9    0-3  0-9    19 20  0-9  2    if  testdate match pattern      return false  else return true

[javascript] regular expression to validate datetime format (MM/DD/YYYY)

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