How to count number of files in each directory

Question

I am able to list all the directories by  find    -type d   I attempted to list the contents of each directory and count the number of files in each directory by using the following command  find    -type d   xargs ls -l   wc -l   But this summed the total number of lines returned by  find    -type d   xargs ls -l   Is there a way I can count the number of files in each directory

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Everyone else s solution has one drawback or another   find -type d -readable -exec sh -c  printf   s     1   ls -1UA   1    wc -l  sh          Explanation    -type d  we re interested in directories  -readable  We only want them if it s possible to list the files in them  Note that find will still emit an error when it tries to search for more directories in them  but this prevents calling -exec for them  -exec sh -c BLAH sh         for each directory  run this script fragment  with  0 set to sh and  1 set to the filename  printf   s     1   portably and minimally print the directory name  followed by only a space  not a newline  ls -1UA  list the files  one per line  in directory order  to avoid stalling the pipe   excluding only the special directories   and    wc -l  count the lines

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find   -type f -printf   h n    sort   uniq -c  gives for example     5     4   aln   5   aln iq   4   bs   4   ft   6   hot

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This will give the overall count   for file in     do echo   file - gt    ls  file   wc -l    done   cut -d     -f 3  py --ji -l  numpy sum l

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find   -type f   cut -d  -f2   sort   uniq -c    find  -type f to find all items of the type file cut -d  -f2 to cut out their specific folder sort to sort the list of foldernames uniq -c to return the number of times each foldername has been counted

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You could arrange to find all the files  remove the file names  leaving you a line containing just the directory name for each file  and then count the number of times each directory appears   find   -type f   sed  s              sort   uniq -c   The only gotcha in this is if you have any file names or directory names containing a newline character  which is fairly unlikely   If you really have to worry about newlines in file names or directory names  I suggest you find them  and fix them so they don t contain newlines  and quietly persuade the guilty party of the error of their ways      If you re interested in the count of the files in each sub-directory of the current directory  counting any files in any sub-directories along with the files in the immediate sub-directory  then I d adapt the sed command to print only the top-level directory   find   -type f   sed -e  s                    1   -e  s                    sort   uniq -c   The first pattern captures the start of the name  the dot  the slash  the name up to the next slash and the slash  and replaces the line with just the first part  so     dir1 dir2 file1   is replaced by    dir1    The second replace captures the files directly in the current directory  they don t have a slash at the end  and those are replace by     The sort and count then works on just the number of names

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I tried with some of the others here but ended up with subfolders included in the file count when I only wanted the files  This prints   folder path lt tab gt nnn with the number of files  not including subfolders  for each subfolder in the current folder   for d in  find   -type d -print   do    echo -e   d t  find  d -maxdepth 1 -type f -print   wc -l   done

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THis could be another way to browse through the directory structures and provide depth results    find   -type d    awk   print  echo -n     0      ls -l   0    grep -v total   wc -l       sh

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This should return the directory name followed by the number of files in the directory   findfiles         echo   1    find   1  -maxdepth 1 -type f   wc -l     export -f findfiles  find    -type d -exec bash -c  findfiles   0           Example output      6   foo 1   foo bar 2   foo bar bazzz 0   foo bar baz 4   src 4   The export -f is required because the -exec argument of find does not allow executing a bash function unless you invoke bash explicitly  and you need to export the function defined in the current scope to the new shell explicitly

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I combined  glenn jackman s answer and  pcarvalho s answer in comment list  there is something wrong with pcarvalho s answer because the extra style control function of character      backtick     My script can accept path as an augument and sort the directory list as ls -l  also it can handles the problem of  space in file name       bin bash OLD IFS   IFS  IFS    n  for dir in   find  1 -maxdepth 1 -type d   sort    do     files    dir         printf   5d  s n      files        dir  done FS   OLD IFS    My first answer in stackoverflow  and I hope it can help someone

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A super fast miracle command  which recursively traverses files to count the number of images in a directory and organize the output by image extension   find   -type f   sed -e  s           sort   uniq -c   sort -n   grep -Ei   tiff bmp jpeg jpg png gif      Credits  https   unix stackexchange com a 386135 354980

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This can also be done with looping over ls instead of find  for f in     do echo   f - gt    ls  f   wc -l    done  Explanation   for f in     - loop over all directories  do echo   f - gt  - print out each directory name    ls  f   wc -l  - call ls for this directory and count lines

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Slightly modified version of Sebastian s answer using find instead of du  to exclude file-size-related overhead that du has to perform and that is never used     find    -mindepth 2 -type f   cut -d  -f2   sort   uniq -c   sort -nr   -mindepth 2 parameter is used to exclude files in current directory  If you remove it  you ll see a bunch of lines like the following     234 dir1   123 dir2     1 file1     1 file2     1 file3               1 fileN    much like the du-based variant does   If you do need to count the files in current directory as well  use this enhanced version     find    -mindepth 2 -type f   cut -d  -f2   sort  amp  amp  find    -maxdepth 1 -type f   cut -d  -f1      uniq -c   sort -nr   The output will be like the following     234 dir1   123 dir2    42

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Here s one way to do it  but probably not the most efficient   find -type d -print0   xargs -0 -n1 bash -c  echo -n   1    ls -1   1    wc -l  --   Gives output like this  with directory name followed by count of entries in that directory   Note that the output count will also include directory entries which may not be what you want     c fa l 0   a 4   a c 0   a a 1   a a b 0

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Assuming you have GNU find  let it find the directories and let bash do the rest   find   -type d -print0   while read -d    -r dir  do     files    dir         printf   5d files in directory  s n      files        dir  done

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I edited the script in order to exclude all node modules directories inside the analyzed one  This can be used to check if the project number of files is exceeding the maximum number that the file watcher can handle  find   -type d   -path  quot  node modules  quot  -print0   while read -d    -r dir  do     files   quot  dir quot         printf  quot  5d files in directory  s n quot   quot    files     quot   quot  dir quot  done  To check the maximum files that your system can watch  cat  proc sys fs inotify max user watches  node modules folder should be added to your IDE editor excluded paths in slow systems  and the other files count shouldn t ideally exceed the maximum  which can be changed though

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Easy way to recursively find files of a given type   In this case   jpg files for all folders in current directory   find   -name   jpg -print   wc -l

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This prints the file count per directory for the current directory level   du -a   cut -d  -f2   sort   uniq -c   sort -nr

[linux] How to count number of files in each directory?

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