[javascript] Sum values from an array of key-value pairs in JavaScript

I have defined a JavaScript variables called myData which is a new Array like this:

var myData = new Array(['2013-01-22', 0], ['2013-01-29', 0], ['2013-02-05', 0],
             ['2013-02-12', 0], ['2013-02-19', 0], ['2013-02-26', 0], 
             ['2013-03-05', 0], ['2013-03-12', 0], ['2013-03-19', 0], 
             ['2013-03-26', 0], ['2013-04-02', 21], ['2013-04-09', 2]);

I am wondering if it is possible to sum the number values found in the array (ex. 0+0+21+2+0 and so on) and have probably a variable with the result that I can use outside of the script tag because I have 7 of this kind of arrays corresponding for each of the day in the week. I want to make a comparison afterwards based on that. That is the most preferred method for this kind of actions if is possible?

The javascript built-in reduce for Arrays is not a standard, but you can use underscore.js:

var data = _.range(10);
var sum = _(data).reduce(function(memo, i) {return memo + i});

which becomes

var sumMyData = _(myData).reduce(function(memo, i) {return memo + i[1]}, 0);

for your case. Have a look at this fiddle also.

You can use the native map method for Arrays. map Method (Array) (JavaScript)

var myData = new Array(['2013-01-22', 0], ['2013-01-29', 0], ['2013-02-05', 0],
             ['2013-02-12', 0], ['2013-02-19', 0], ['2013-02-26', 0], 
             ['2013-03-05', 0], ['2013-03-12', 0], ['2013-03-19', 0], 
             ['2013-03-26', 0], ['2013-04-02', 21], ['2013-04-09', 2]);
var a = 0;
myData.map( function(aa){ a += aa[1];  return a; });

a is your result

If you want to discard the array at the same time as summing, you could do (say, stack is the array):

var stack = [1,2,3],
    sum = 0;
while(stack.length > 0) { sum += stack.pop() };

Or in ES6

values.reduce((a, b) => a + b),

example:

[1,2,3].reduce((a, b)=>a+b) // return 6

I would use reduce

var myData = new Array(['2013-01-22', 0], ['2013-01-29', 0], ['2013-02-05', 0], ['2013-02-12', 0], ['2013-02-19', 0], ['2013-02-26', 0], ['2013-03-05', 0], ['2013-03-12', 0], ['2013-03-19', 0], ['2013-03-26', 0], ['2013-04-02', 21], ['2013-04-09', 2]);

var sum = myData.reduce(function(a, b) {
    return a + b[1];
}, 0);

$("#result").text(sum);

Available on jsfiddle

where 0 is initial value

Array.reduce((currentValue, value) => currentValue +value,0)

or

Array.reduce((currentValue, value) =>{ return currentValue +value},0)

or

[1,3,4].reduce(function(currentValue, value) { return currentValue + value},0)

You could use the Array.reduce method:

const myData = [_x000D_
  ['2013-01-22', 0], ['2013-01-29', 0], ['2013-02-05', 0],_x000D_
  ['2013-02-12', 0], ['2013-02-19', 0], ['2013-02-26', 0], _x000D_
  ['2013-03-05', 0], ['2013-03-12', 0], ['2013-03-19', 0], _x000D_
  ['2013-03-26', 0], ['2013-04-02', 21], ['2013-04-09', 2]_x000D_
];_x000D_
const sum = myData_x000D_
  .map( v => v[1] )                                _x000D_
  .reduce( (sum, current) => sum + current, 0 );_x000D_
  _x000D_
console.log(sum);

See MDN

I think the simplest way might be:

values.reduce(function(a, b){return a+b;})

Creating a sum method would work nicely, e.g. you could add the sum function to Array

Array.prototype.sum = function(selector) {
    if (typeof selector !== 'function') {
        selector = function(item) {
            return item;
        }
    }
    var sum = 0;
    for (var i = 0; i < this.length; i++) {
        sum += parseFloat(selector(this[i]));
    }
    return sum;
};

then you could do

> [1,2,3].sum()
6

and in your case

> myData.sum(function(item) { return item[1]; });
23

Edit: Extending the builtins can be frowned upon because if everyone did it we would get things unexpectedly overriding each other (namespace collisions). you could add the sum function to some module and accept an array as an argument if you like. that could mean changing the signature to myModule.sum = function(arr, selector) { then this would become arr

Old way (if you don't now the length of arguments/parameters)

 >> function sumla1(){

    result=0
    for(let i=0; i<arguments.length;i++){

        result+=arguments[i];

    }
    return result;
    }
    >> sumla1(45,67,88);
    >> 200

ES6 (destructuring of array)

>> function sumla2(...x){return x.reduce((a,b)=>a+b)}
>>
>> sumla2(5,5,6,7,8)
>>
>> 31
>>
>> var numbers = [4, 9, 16, 25];
>> sumla2(...numbers);
>> 54