How do I print the percent sign in c

Question

I am a beginner in C  and I was wondering why this program does not print   sign   The code is    include lt stdio h gt   main          printf            getch

User · Accepted Answer

Your problem is that you have to change      printf          to   printf          Or you could use ASCII  code and write   printf   c   37

User · Answer

there s no explanation in this topic why to print a percentage sign one must type    and not for example escape character with percentage -      from comp lang c FAQ list    Question 12 6       The reason it s tricky to print   signs with printf is that   is   essentially printf s escape character  Whenever printf sees a    it   expects it to be followed by a character telling it what to do next    The two-character sequence    is defined to print a single         To understand why    can t work  remember that the backslash   is the   compiler s escape character  and controls how the compiler interprets   source code characters at compile time  In this case  however  we want   to control how printf interprets its format string at run-time  As far   as the compiler is concerned  the escape sequence    is undefined  and   probably results in a single   character  It would be unlikely for   both the   and the   to make it through to printf  even if printf were   prepared to treat the   specially    so the reason why one must type printf        to print single   is that s what is defined in printf function    is an escape character of printf s  and   of compiler

User · Answer

Use        The man page describes this requirement              A     is written   No argument is converted   The complete conversion specification is

User · Answer

Try printing out this way   printf

[c] How do I print the percent sign(%) in c

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